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3 years ago

6. Positive uses of radioactive decay used by humans would not include

Chemistry

1 answer:

spin [16.1K]3 years ago

7 0

Answer:

Explanation:

All are good

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Please help~~ thank you so much

deff fn [24]

Answer:

c. 2 and 3

Explanation:

Ca(NO3)2 names calcium nitrate.

Ca metal, O, N - nonmetals, so Ca(NO3)2 is ionic compound.

It is solid and white.

4 0

3 years ago

Both Sydney, Australia and Guangzhou, China are on the East coasts of continents in the Pacific Ocean. Why are their yearly temp

cestrela7 [59]

Answer:

All of the above

Explanation:

(I'm assuming you meant to put Australia in the options)

Australia is in the southern hemisphere and has its summer in December etc. and Winter in July etc.

China is in the northern hemisphere and has its summer in July etc and Winter in December etc.

6 0

3 years ago

In which substance does sharing of electrons between two atoms occur?

Ivenika [448]

Answer:

A. SO4 2−

Explanation:

SO₄²⁻

A covalent bond is a bond that forms from sharing of electrons between two atoms. Here, the two atoms combined must have a very low electronegative difference between them, usually 0. Electronegativity deals with the tendency of an atom to attract electrons to itself.

Oxygen and sulfur shows similar tendencies. Since the two atoms shows a strong affinity for their valence electrons in order to complete the octet. This will lead to the eventual sharing of the valence electrons.

3 0

3 years ago

Read 2 more answers

Using your periodic table, what is the number of protons in an atom of sodium

Romashka-Z-Leto [24]

Answer:

It would be 11

3 0

3 years ago

Methanol has a normal boiling point of 64.6C and a heat of vaporization of 35.2 kJ/mol. What is the vapor pressure (in Torr) of

DENIUS [597]

Answer:

vapor pressure of methanol at 12.0C = 75.09 torr

Explanation:

Using Clausius Clapeyron equation

, we have that

ln (P2/P1)= (ΔHvap /R) (1/T1 - 1/T2)

Given

At Normal boiling point,

Temperature T1= 64.6°C = 64.6 + 273 = 337.6 K, Pressure,P1 = 1 atm

Heat of vaporization = 35.2 kJ/mol

Changing to J/mol

=35.2 x 1000= 35200 J/mol

Temperature , T2 = 12.0oC = 12 + 273 = 285 K

Using gas constant, R = 8.314 J/mol.K

ln (P2/P1)= -(ΔHvap /R) (1/T1 - 1/T2)

ln (P2/ 1 atm) = (35200 J/mol/ (8.314 J/mol.K) X( 1/337.6 - 1/285)

ln (P2/ 1 atm) =4,233.822 X (0.00296-0.003508)

ln (P2/ 1 atm) = 4,233.822468 x-0.0005466866

ln (P2/ 1 atm)= -2.31457

P2 = e^⁻2.31457 x 1 atm

P2=0.098808atm

= 0.098808atm x760 = 75.09 torr

7 0

2 years ago