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Answer:
0.40
Step-by-step explanation:
Members who run only long distance = 8%
So, probability that a member will run only long distance = P(A) = 0.08
Members who compete only in field events = 32%
So, probability that a member will compete only in field events = P(B) 0.32
Members who are sprinters = 12%
So, probability that a member is sprinter = P(C) 0.12
We have to calculate the probability that a randomly chosen team member runs only long-distance or competes only in field events. i.e we have to find P(A or B). Since these events cannot occur at the same time, we can write:
P(A or B) = P(A) + P(B)
Using the values, we get:
P(A or B) = 0.08 + 0.32 = 0.40
Thus, the probability that a randomly chosen team member runs only long-distance or competes only in field events is 0.40
Answer:
1. S.A. = 4350 cm²
2. S.A. = 864 cm²
3. S.A. = 240 cm²
4. S.A. = 224 m²
5. S.A. = 301.6 in.²
6. S.A. = 6,082.1 cm²
7. S.A. = 923.6 in.²
Step-by-step explanation:
1. Surface area of the rectangular prism = 2(LW + LH + WH)
L = 45 cm
W = 25 cm
H = 15 cm
S.A. = 2(45*25 + 45*15 + 25*15)
S.A. = 4350 m²
2. Surface area of the cube = 6a²
a = 12 cm
S.A. = 6(12²)
S.A. = 864 cm²
3. Surface area of triangular prism = bh + (s1 + s2 + s3)*H
b = 4 cm
h = 6 cm
s1 = 4 cm
s2 = 7 cm
s3 = 7 cm
H = 12 cm
Plug in the values
S.A. = 4*6 + (4 + 7 + 7)*12
S.A. = 24 + (18)*12
S.A. = 24 + 216
S.A. = 240 cm²
4. Surface area of the square based pyramid = area of the square base + 4(area of 1 triangular face)
S.A. = (8*8) + 4[(8*10)/2]
S.A. = 64 + 4(40)
S.A. = 64 + 160
S.A. = 224 cm²
5. Surface area of the cone = πrl + πr²
r = 6 in.
l = 10 in.
S.A. = π*6*10 + π*r²
S.A. = 60π + 36π
S.A. = 301.592895
S.A. = 301.6 in.² (nearest tenth)
6. Surface area of the sphere = 4πr²
r = 22 cm
S.A. = 4*π*22²
S.A. = 1,936π
S.A. = 6,082.1 cm² (nearest tenth)
7. Surface area of the cylinder = 2πrh + 2πr²
r = 7 in.
h = 14 in.
S.A. = 2*π*7*14 + 2*π*7²
S.A. = 923.6 in.² (nearest tenth)
Answer:
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Step-by-step explanation:
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Answer:
the answer is B
Step-by-step explanation:
do 160/3