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3 years ago

If the net force on an object is 0 N, the forces are considered unbalanced. :true or false?

Chemistry

1 answer:

katovenus [111]3 years ago

3 0

Answer:

False, the object is stationary therefore the object is balanced.

Explanation:

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12.23 g of ammonia (NH3) are dissolved in enough water to make 560.0 mL of solution. How many moles of NH3 are added to the wate

Karolina [17]

Answer:

0.719 moles of NH₃

Explanation:

Molar mass of ammonia 17 g/mol

Mass of amonia = 12.23 g

Mass / Molar mass = Moles

12.23 g / 17 g/mol = 0.719 moles

4 0

3 years ago

Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. 4.90 g of su

GaryK [48]

Answer:

Mass H2SO4 = 3.42 grams

Mass of lead acetate = 0 grams

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 1.81 grams

Explanation:

Step 1: Data given

Mass of sulfuric acid = 4.90 grams

Molar mass of sulfuric acid = 98.08 g/mol

Mass of lead acetate = 4.90 grams

Molar mass of lead acetate = 325.29 g/mol

Step 2: The balanced equation

H2SO4 + Pb(C2H3O2)2 → PbSO4 + 2CH3COOH

Step 3: Calculate moles

Moles = mass / molar mass

Moles H2SO4 = 4.90 grams / 98.08 g/mol

Moles H2SO4 = 0.0500 moles

Moles lead acetate = 4.9 grams / 325.29 g/mol

Moles lead acetate = 0.0151 moles

Step 4: Calculate the limiting reactant

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

The limiting reactant is lead acetate. It will completzly be consumed (0.0151 moles). H2SO4 is in excess. There will react 0.0151 moles. There will remain 0.0500 - 0.0151 = 0.0349 moles

Step 5: Calculate moles of products

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

For 0.0151 moles lead acetate we'll have 0.0151 moles PbSO4 and 2*0.0151 = 0.0302 moles CH3COOH

Step 6: Calculate mass

Mass = moles * molar mass

Mass H2SO4 = 0.0349 moles * 98.08 g/mol

Mass H2SO4 = 3.42 grams

Mass PbSO4 = 0.0151 moles * 303.26 g/mol

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 0.0302 moles * 60.05 g/mol

Mass of CH3COOH = 1.81 grams

5 0

4 years ago

Silver metal is expensive and should always be recycled. If your lab has 0.500 L of silver nitrate solution (2 .00 mol* L^ -1 )

Paladinen [302]

Mass of Copper : 63.5 g

<h3>Further explanation</h3>

Given

Reaction

Cu(s)+2AgNO₃ (aq) ⇒Cu(NO₃)₂ (aq)+2Ag(s)

Required

Mass of Copper

Solution

mol of Silver nitrate :

= M x V

= 2 mol/L x 0.5 L

= 1

From the equation, mol ratio of Cu : AgNO₃ = 1 : 2, so mol Cu = 1

Mass of Cu(Ar=63.5 g/mol) :

= mol x Ar

= 1 x 63.5

= 63.5 g

5 0

3 years ago

Analysis of a rock sample shows that it contains 6.25% of its original uranium-235. How old is the rock? How do you know?

nadya68 [22]

Answer:

$2.82\cdot 10^9 y$

Explanation:

A radioactive isotope is an isotope that undergoes nuclear decay, breaking apart into a smaller nucleus and emitting radiation during the process.

The half-life of an isotope is the amount of time it takes for a certain quantity of a radioactive isotope to halve.

For a radioactive isotope, the amount of substance left after a certain time t is:

$m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}}$ (1)

where

$m_0$ is the mass of the substance at time t = 0

m(t) is the mass of the substance at time t

$\tau$ is the half-life of the isotope

In this problem, the isotope is uranium-235, which has a half-life of

$\tau=7.04\cdot 10^8 y$

We also know that the amount of uranium left in the rock sample is 6.25% of its original value, this means that

$\frac{m(t)}{m_0}=\frac{6.25}{100}$

Substituting into (1) and solving for t, we can find how much time has passed:

$t=-\tau log_2 (\frac{m(t)}{m_0})=-(7.04\cdot 10^8) log_2 (\frac{6.25}{100})=2.82\cdot 10^9 y$

5 0

3 years ago

Potassium and sodium chloride are similar in charge and they both have the same anion. When comparing sodium chloride (36 g / 1

lesya [120]

Sodium Chloride has a higher solubility.

7 0

4 years ago

If the net force on an object is 0 N, the forces are considered unbalanced. :true or false?​

If the net force on an object is 0 N, the forces are considered unbalanced. :true or false?