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Kruka [31]
3 years ago
10

Using PEP or PrEP can reduce the chances of becoming infected for a person exposed to HIV.

Chemistry
2 answers:
Elodia [21]3 years ago
7 0
True i hope this helps
Sergio039 [100]3 years ago
5 0

Answer:

trueeee

Explanation:

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How long will a current of 0.995 A need to be passed through water (containing H2SO4) for 5.00 L of O2 to be produced at STP
DIA [1.3K]

Answer:

24 hours

Explanation:

The computation is shown below:

The needed mole of O_2 is

= 5 ÷22.4 = n

Also 1 mole of O_2 required four electric charge

Now the charge needed is

= n × 4 × 96,500 C

= 4 × 96,500 × 5 c ÷ 22.4

= 86160.714 C

Now

q = i t

t = q ÷ i

= 86160.714 C ÷ 0.995

= 86593.7 seconds

= 24 hours

Hence, the correct option is A.

3 0
3 years ago
Which rule for assigning oxidation numbers is correct?
LenKa [72]
Hydrogen is usually –1. This is INCORRECT. The oxidation number for H is +1.
Oxygen is usually –2. This is CORRECT.
A pure group 1 element is +1. This is INCORRECT. It does not follow. This will depend on the other elements and the overall charge.
A monatomic ion is 0. This is INCORRECT. Diatomic ion is 0.
4 0
3 years ago
Read 2 more answers
Irony can be seen in which of the following lines? (Mark all that apply.)
Flura [38]

Answer:

Awnser Is B

Explanation:

5 0
4 years ago
Given the standard enthalpy changes for the following two reactions:
lawyer [7]

Answer:

ΔH° = -186.2 kJ

Explanation:

Hello,

This case in which the Hess method is applied to compute the required chemical reaction. Thus, we should arrange the given first two reactions as:

(1) it is changed as:

SnCl2(s) --> Sn(s) + Cl2(g)...... ΔH° = 325.1 kJ

That is why the enthalpy of reaction sign is inverted.

(2) remains the same:

Sn(s) + 2Cl2(g) --> SnCl4(l)......ΔH° = -511.3 kJ

Therefore, by adding them, we obtain the requested chemical reaction:

(3) SnCl2(s) + Cl2(g) --> SnCl4(l)

For which the enthalpy change is:

ΔH° = 325.1 kJ - 511.3 kJ

ΔH° = -186.2 kJ

Best regards.

7 0
3 years ago
Read 2 more answers
How many moles of salt are in 13.8 g of sodium chloride?
Hoochie [10]

Answer: 0.24 moles

Explanation:

Molecular Mass of NaCl (23 + 35.5) = 58.5g

58.5g of Sodium Chloride -------> 1 mole of NaCl

∴ 13.8g of Sodium Chloride  ------>  1 ÷58.5 x  13.8 = 0.2358974  ≈    0.24moles

                                                         -  

3 0
3 years ago
Read 2 more answers
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