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4 years ago

Where is the only place the weak necular force can be seen

Chemistry

2 answers:

Butoxors [25]4 years ago

5 0

The weak force is carried by the W and Z bosons. You are welcome

kykrilka [37]4 years ago

3 0

I’m not that smart sorry

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Which molucules are pure elements?

IrinaK [193]

None, because molecules are a group of two (or more) electrically bonded atoms. But there are gases not bonded due to their stability.

6 0

3 years ago

Jules Verne wrote the book Twenty Thousand Leagues Under the Sea. If one league - 5.556 km and one furlong - 660.0 feet, how man

Vlad [161]

Answer:

The Nautilus travel $5.52\times 10^5 furlongs$ .

Explanation:

Given: 1 league = 5.556 km

1 furlong = 660.0 feet

To find: 20,000 leagues = ? furlongs

Solution:

20,000 leagues = $20,000\times 5.556 km =111,120 km$

1 km = 3280.84 feet

$111,120 km= 111,120\times 3280.84 feet=364,566,940.8 feet$

If ,1 furlong = 660.0 feet.

Then, 1 foot = $\frac{1}{660.0} furlong$

$364,566,940.8 feet=364,566,940.8 \times \frac{1}{660.0}$

$=552,374.1524 furlongs\approx 5.52\times 10^5 furlongs$

7 0

3 years ago

Consider the following reaction: 2 NO(g) + 5 H2(g) → 2 NH3(g) + 2 H2O(g) Which set of solution maps would be needed to calculate

Leto [7]

Answer : The correct option is, (I) $gNO\rightarrow molNO\rightarrow molNH_3\rightarrow gNH_3$

Solution : Given,

Mass of NO = 45.8 g

Mass of $H_2$ = 12.4 g

Molar mass of NO = 30 g/mole

Molar mass of $H_2$ = 2 g/mole

Molar mass of $NH_3$ = 17 g/mole

First we have to calculate the moles of NO and $O_2$ .

$\text{ Moles of }NO=\frac{\text{ Mass of }NO}{\text{ Molar mass of }NO}=\frac{45.8g}{30g/mole}=1.53moles$

$\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{12.4g}{2g/mole}=6.20moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2NO(g)+5H_2(g)\rightarrow 2NH_3(g)+2H_2O(g)$

From the balanced reaction we conclude that

As, 2 mole of $NO$ react with 5 mole of $H_2$

So, 1.53 moles of $NO$ react with $\frac{1.53}{2}\times 5=3.82$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $NO$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 2 mole of $NO$ react to give 2 mole of $NH_3$

So, 1.53 mole of $NO$ react to give 1.53 mole of $NH_3$

Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

$\text{ Mass of }NH_3=(1.53moles)\times (17g/mole)=26.0g$

Therefore, the maximum mass of $NH_3$ produced 26.0 grams.

7 0

3 years ago

The enthalpy of combustion of benzoic acid (C6H5COOH) is commonly used as the standard for calibrating constant-volume bomb calo

Anit [1.1K]

<h3>Answer:</h3>

28.96 kJ/°C

<h3>Explanation:</h3>

We are given;

Enthalpy change (ΔH) = −3226.7 kJ/mol
The reaction is exothermic since the heat change is negative;
Mass of benzoic acid = 3.1007 g
Temperature change (21.84°C to 24.67°C) = 2.83°C

We are required to find the heat capacity of benzoic acid;

<h3>Step 1: Moles of benzoic acid </h3>

Moles = Mass ÷ molar mass

Molar mass of benzoic = 122.12 g/mol

Therefore;

Moles = 3.1007 g ÷ 122.12 g/mol

= 0.0254 moles

<h3>Step 2: Determine the specific heat capacity </h3>

Heat change for 1 mole = 3226.7 kJ

Moles of Benzoic acid = 0.0254 moles

But;

Specific heat capacity × ΔT = Moles × Heat change

cΔT = nΔH

Therefore;

Specific heat capacity,c = nΔH ÷ ΔT

= (3226.7 kJ × 0.0254 moles) ÷ 2.83°C

= 28.96 kJ/°C

Therefore, the specific heat capacity of benzoic acid is 28.96 kJ/°C

7 0

4 years ago

Why are supergiant so bright?

Yuliya22 [10]

Because supergiants are so massive, the core temperature gets much hotter than in giants, so supergiants can fuse elements heavier than hydrogen and helium. But to support their tremendous mass, supergiants burn up their fuel much more quickly.

5 0

3 years ago

Read 2 more answers