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3 years ago

In a 0.01 M solution of HCl, Litmus will be

2 answers:

6 0

In a 0.01 M solution of HCl, Litmus will be red. Litmus paper will turn into red in acidic conditions. Hydrochloric acid is an acid. Litmus is an indicator for acidity and alkalinity made from inchens.

Viefleur [7K]3 years ago

3 0

Explanation:

A solution with pH less than 7 will be acidic in nature and it will change color of blue litmus into red.

For example, HCl is a strong acid as it dissociates to give hydrogen ions and chlorine ions.

A solution with pH more than 7 will be basic in nature and it will change color of red litmus into blue.

A solution with pH equal to 7 will be neutral in nature and it will not change the color any litmus paper.

Thus, we can conclude that in a 0.01 M solution of HCl, litmus will be red.

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For a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k, calculate the inner diameter if you are designing for

bonufazy [111]

The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m

<h3>What is Stack Height ?</h3>

Stack height means the distance from the ground-level elevation at the base of the stack to the crown of the stack.

If a stack arises from a building or other structure, the ground-level elevation of that building or structure will be used as the base elevation of the stack.

Given is a steel stack that exhausts 1,200 cu.m/min of gases

P= 1 atm and

T= 400 K

maximum expected wind speed at stack height of 12 m/s

The formula for the diameter of chimney

$\rm d=\sqrt{\dfrac{4Q}{\pi v} }$

Q =1200 cu.m/min

= 1200 * 0.0166 = 19.92 cu.m/sec

Velocity = 12m/s

$\rm d=\sqrt{\dfrac{4\times 19.92}{3.14*12} }\\$

d= 1.45 m

Therefore The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m.

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2 years ago

How are monomers and polymers related?

Korvikt [17]

Answer:Complex carbohydrates are formed from monosaccharides, nucleic acids are formed from mononucleotides, and proteins are formed from amino acids. There is great diversity in the manner by which monomers can combine to form polymers. For example, glucose monomers are the constituents of starch, glycogen, and cellulos

Explanation:

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3 years ago

How many atoms are in 25.00 g of B.

iren2701 [21]

Answer:

$\boxed {\boxed {\sf 1.393 *10^{24} \ atoms \ B}}$

Explanation:

1. Convert Grams to Moles

Use the molar mass (found on the Periodic Table) to convert from grams to moles.

Boron (B): 10.81 g/mol

Use this value as a ratio.

$\frac {10.81 \ g \ B }{1 \ mol \ B}$

Multiply by the given number of grams.

$25.00 \ g \ B *\frac {10.81 \ g \ B }{1 \ mol \ B}$

Flip the ratio so the grams of boron cancel out.

$25.00 \ g \ B *\frac {1 \ mol \ B }{10.81 \ g \ B}$

$25.00 *\frac {1 \ mol \ B }{10.81 }$

$\frac {25.00 \ mol \ B }{10.81 }=2.312673451 \ mol \ B$

2. Convert Moles to Atoms

We use Avogadro's Number, 6.02*10²³: the number of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of boron.

$\frac {6.02*10^{23} \ atoms \ B} {1 \ mol \ B}$

Multiply by the number of moles we calculated.

$2.312673451 \ mol \ B *\frac {6.02*10^{23} \ atoms \ B} {1 \ mol \ B}$

The moles of boron cancel.

$2.312673451 *\frac {6.02*10^{23} \ atoms \ B} {1 }$

$2.312673451 *6.02*10^{23} \ atoms \ B} =1.39269195*10^{24} \ atoms \ B$

The original value of grams has 4 significant figures, so our answer should have the same. For the number we calculated, that is the thousandth place.

$1.392\underline69195*10^{24} \ atoms \ B$

The 6 tells us to round the 2 to a 3.

$1.393 *10^{24} \ atoms \ B$

25.00 grams of boron is equal to 1.393*10²⁴ atoms.

6 0

3 years ago

Suppose 20.8 g of sodium iodide is dissolved in 250. mL of a 0.70 M aqueous solution of silver nitrate. Calculate the final mola

gtnhenbr [62]

Answer:

[Ag+] = [NO3-] = 0.700M

0.555M = [Na+] = [I-]

Explanation:

To solve this question we need to find the moles of sodium iodide, NaI, using its molar mass -. With the moles and the volume we can find the molarity of Na+ and I-. The molarity of the ions of silver nitrate, AgNO3 doesn't change because we are assuming the volume doesn't change:

Molarity Ag⁺ = Molarity NO₃⁻ = 0.700M

Moles NaI -Molar mass: 149.89g/mol-

20.8g NaI * (1mol/149.89g) = 0.0139 moles NaI

Molarity:

0.0139 moles NaI / 0.250L = 0.555M = [Na+] = [I-]

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3 years ago

The trend for ionization energy is a general increase from left to right across a period. However, phosphorus (P) is found to ha

stiv31 [10]

₁₅P 1s²2s²2p⁶3s²3p³
₁₆S 1s²2s²2p⁶3s²3p⁴
It is because: 1) phosphorus have 3 unpaired electrons in 3p shell, and that is more stable than 3p⁴ in sulfur, so it ie easier to remove 1 paired electron in sulphur to became 3p³.
2) repulsion in 3p shell in sulfur between 2 paired electrons is higher, so it is easier to remove that electron.

5 0

3 years ago

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