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3 years ago

12

How would I do this

1 answer:

Solnce55 [7]3 years ago

4 0

Answer:

the ramp must be lowered

Step-by-step explanation:

Use the definition of the sine function to find the height of a ramp that is 8°.

Sine = Opposite/Hypotenuse

sin(8°) = height/8

height = 8×sin(8°) = 1.11

The height Nate's dad allows is 1.11 feet. At 1.5 feet, the ramp is too high.

The ramp must be lowered.

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If RS = 33.6 and QS = 79, find QR.

babunello [35]

The answer is D. 45.4

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4 years ago

Read 2 more answers

A fabricator is hired to make a 27 foot long solid metal railing for the stairs at a local library. the railing is 2.5 inches hi

Furkat [3]

The complete question in the attached figure

we know that
volume of <span>the railing=volume of a rectangular prism+volume </span><span>a half cylinder

convert 27 ft to inches--------> 27*12-----> 324 in
step 1
find the </span>volume of a rectangular prism
volume of a rectangular prism=L*W*H-----> 324*2.5*1.25-----> 1012.5 in³

step 2
find volume a half cylinder
volume a half cylinder=(1/2)*pi*r²*h
r=1.25 in
h= 324 in
volume a half cylinder=(1/2)*pi*1.25²*324---> 795.22 in³

step 3
volume of the railing=volume of a rectangular prism+volume a half cylinder
volume of the railing=1012.5+795.22------>1807.72 in³------> 1808 in³

the answer is
1808 in³

7 0

3 years ago

I need help solving for x please

Bess [88]

Answer:

x is 55 degrees because the whole angle is a total of 180 degrees. All you have to do is do 180 minus the given angle, 125

8 0

4 years ago

Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y

Drupady [299]

Answer:

$V = \frac{\pi^2}{8}$

$V = 1.23245$

Step-by-step explanation:

Given

$y = \cos 2x$

$y = 0; x = 0; x = \frac{\pi}{4}$

Required

Determine the volume of the solid generated

Using the disk method approach, we have:

$V = \pi \int\limits^a_b {R(x)^2} \, dx$

Where

$y = R(x) = \cos 2x$

$a = \frac{\pi}{4}; b =0$

So:

$V = \pi \int\limits^a_b {R(x)^2} \, dx$

Where

$y = R(x) = \cos 2x$

$a = \frac{\pi}{4}; b =0$

So:

$V = \pi \int\limits^a_b {R(x)^2} \, dx$

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {(\cos 2x)^2} \, dx$

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {\cos^2 (2x)} \, dx$

Apply the following half angle trigonometry identity;

$\cos^2(x) = \frac{1}{2}[1 + \cos(2x)]$

So, we have:

$\cos^2(2x) = \frac{1}{2}[1 + \cos(2*2x)]$

$\cos^2(2x) = \frac{1}{2}[1 + \cos(4x)]$

Open bracket

$\cos^2(2x) = \frac{1}{2} + \frac{1}{2}\cos(4x)$

So, we have:

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {\cos^2 (2x)} \, dx$

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {[\frac{1}{2} + \frac{1}{2}\cos(4x)]} \, dx$

Integrate

$V = \pi [\frac{x}{2} + \frac{1}{8}\sin(4x)]\limits^{\frac{\pi}{4}}_0$

Expand

$V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})] - [\frac{0}{2} + \frac{1}{8}\sin(4*0)])$

$V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})] - [0 + 0])$

$V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})])$

$V = \pi ([{\frac{\pi}{8} + \frac{1}{8}\sin(\pi)])$

$\sin \pi = 0$

So:

$V = \pi ([{\frac{\pi}{8} + \frac{1}{8}*0])$

$V = \pi *[{\frac{\pi}{8}]$

$V = \frac{\pi^2}{8}$

or

$V = \frac{3.14^2}{8}$

$V = 1.23245$

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3 years ago

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What times itself equils that number

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4 years ago