How would I do this
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A. If you plot the points in a graph, it would look like that shown in the picture attached. If we use linear regression, the correlation is very poor. The coefficient of correlation (r2) is only 0.0017. There is no linear relationship between time and velocity.
B. The slope of the graph is equal to y2-y1/x2-x1, In this case, it would specifically be v2-v1/t2-t1
Slope = 0.8-0.2/20-10 = 0.06 miles/s^2
The slope represents the acceleration at time 10 to 20 minutes.
C. The table in the graph shows causation rather than correlation. The points in the data occur in a sequential manner.
B. The slope of the graph is equal to y2-y1/x2-x1, In this case, it would specifically be v2-v1/t2-t1
Slope = 0.8-0.2/20-10 = 0.06 miles/s^2
The slope represents the acceleration at time 10 to 20 minutes.
C. The table in the graph shows causation rather than correlation. The points in the data occur in a sequential manner.
Answer: A
Step-by-step explanation:
