5(x + 10)?  A.5x + 10 B.5x + 10x C.5x + 50 D.5 + x + 10.
Answer:
r=63
Step-by-step explanation:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
r/3-(21)=0 r
Simplify —
3
r
— - 21 = 0
3 2.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 3 as the denominator :
21 21 • 3
21 = —— = ——————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Answer:
y = -3x+8
Step-by-step explanation:
formula = y=mx+b
slope is m
y-intercept is b
Answer:
x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4
Step-by-step explanation:
Solve for x:
2 x^2 - 5 x + 5 = 0
Hint: | Using the quadratic formula, solve for x.
x = (5 ± sqrt((-5)^2 - 4×2×5))/(2×2) = (5 ± sqrt(25 - 40))/4 = (5 ± sqrt(-15))/4:
x = (5 + sqrt(-15))/4 or x = (5 - sqrt(-15))/4
Hint: | Express sqrt(-15) in terms of i.
sqrt(-15) = sqrt(-1) sqrt(15) = i sqrt(15):
Answer: x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4
Answer:
The coordinates are (2,8)
Step-by-step explanation:
A hole is where both the numerator and the denominator are zero
f(x)=x^2+4x−12 / x−2
Factor the numerator
f(x) = (x+6) (x-2)/ (x-2)
The hole will occur where x-2 =0
x-2=0
Add 2 to each side
x-2+2 =0+2
x=2
There is a hole at x=2
If we could cancel the x-2 values from the top and bottom, we are left with
f(x) = x+6
At x=2
f(2) = 6+2
f(2) would be 8
The coordinates are (2,8)
There is a hole
