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Tanya [424]
3 years ago
6

Which structural adaptation would help a plant survive better in a shady environment?

Chemistry
1 answer:
Gekata [30.6K]3 years ago
3 0

Answer:C.

large leaves

Explanation: I took the test

You might be interested in
Please help urgent Balance the following word equation:
LekaFEV [45]

Answer:

AlCl3 + 3Na > Al + 3NaCl

Explanation:

AlCl3+Na → Al + NaCl

Al =1 Al=1

Cl =3 Cl = 1

Na=1. Na = 1

so balance

and it would be

Alcl3 + 3Na → Al + 3NaCl

8 0
3 years ago
What is an atom with 2 protons and 4 neutrons
Katena32 [7]
Helium,it has an atomic mass of 4,which means total no. of protons and neutrons,so I think you meant 2 protons and an atomic mass of 4
7 0
3 years ago
Are enzyme-catalyzed reactions examples of homo-<br> geneous or heterogeneous catalysis? Explain.
Tanzania [10]

Answer:Yes,enzymes are catalyzed reactions

Explanation:Enzymes are protein that speeds up chemical reactions. Enzyme catalyzed reaction are divided into two:

Homogeneous reaction

Heterogeneous reaction.

Homogeneous catalysts occupy the same phase as the reaction mixture, while heterogeneous catalysts occupy a different phase.

Acid catalysis, organometallic catalysis, and enzymatic catalysis are examples of homogeneous catalysis.

Vanadium oxide (V2 O5) is a brown/yellow solid on which the oxygen and sulfur dioxide can adsorb in order to react with each other to form sulfuric acid.

8 0
3 years ago
Match each processes with the correct transfer of energy.
sveticcg [70]

freezing-energy lost (exothermic)

sublimation-energy gain (endothermic)

evaporation- energy gain(endothermic)

Melting- energy gain(endothermic)

deposition- energy lost(exothermic)

condensation-energy lost(exothermic)

7 0
3 years ago
A sample compound with a molar mass of 34.00g/mol is found to consist of 0.44g H and 6.92g O. Calculate both empirical and molec
balu736 [363]

Answer:

E.F= OH

M.F=O_{2} H_{2}

Explanation:

Empirical Formula

Step 1: Calculate mols of each element

0.44gH(1 mol H/ 1.008g H)= 0.4365 mol H

*note leave extra sig figs for calculations

6.92gO(1 mol O/ 16 g O)=0.4325 mol O

Step 2: Identify which is the smallest mol

*in this case 0.4365 mol H> 0.4325 mol O so we will use 0.4325 mol O

Step 3: Divide above calculations by the smallest mol

0.4325 mol O/0.4325= 1

0.4365 mol H/0.4325= 1.009 *rounds to 1

Step 4: use calculations as subscripts

Oxygen = 1 so the subscript will 1 (O)

Hydrogen = 1 so the subscript will 1 (H)

making E.F= OH

Molecular Formula:

Step 1: identify  molecular mass and mass from the E.F

the molecular mass is given 34.00g/mol

the mass of the E.F is

(oxygen mass from periodic table)+(hydrogen mass from periodic table)

16+1.008= 17.008

Step 2:Divide the molecular mass by the mass given by the emipirical formula.

\frac{34.00}{17.008}= 1.999 round to 2

Step 3:Multiply the empirical formula (the subscripts) by this number to get the molecular formula.  ANSWER: M.F=2(OH)- O_{2} H_{2}

3 0
3 years ago
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