A Is the answer babez a:)
When water at 50 C is added to ice at -12 C, heat is transferred from hot water to ice.
- Heat given out by water = Heat absorbed by ice
Calculating the heat released by hot water:
ΔT![q = m (4.184\frac{J}{(g.^{0}C)} )](https://tex.z-dn.net/?f=%20%3C%2Fp%3E%3Cp%3Eq%20%3D%20m%20%284.184%5Cfrac%7BJ%7D%7B%28g.%5E%7B0%7DC%29%7D%20%29%20%20)
![(0^{0}C-50^{0}C)](https://tex.z-dn.net/?f=%20%280%5E%7B0%7DC-50%5E%7B0%7DC%29%20%20%20)
Calculating heat absorbed by 16 g of ice: Ice at
is converted to ice at
and then ice at
to water at ![0^{0}C](https://tex.z-dn.net/?f=%200%5E%7B0%7DC%20%20)
ΔT + ![m (Heat of fusion)](https://tex.z-dn.net/?f=%20m%20%28Heat%20of%20fusion%29%20)
+ ![16 g (333.55\frac{J}{g})](https://tex.z-dn.net/?f=%2016%20g%20%28333.55%5Cfrac%7BJ%7D%7Bg%7D%29%20)
q = 405.12 J +5336.8 J =5741.92 J
- Heat given out by water = Heat absorbed by ice
-(![m(4.184\frac{J}{g.^{0}C})(0^{0}C-50^{0}C) = 5741.92 J](https://tex.z-dn.net/?f=%20m%284.184%5Cfrac%7BJ%7D%7Bg.%5E%7B0%7DC%7D%29%280%5E%7B0%7DC-50%5E%7B0%7DC%29%20%3D%205741.92%20J)
m = 27.4 g
Therefore, 27.4 g water at
must be added to 16 g of ice at
to convert to liquid water at ![0^{0}C](https://tex.z-dn.net/?f=%200%5E%7B0%7DC%20%20)
Answer:
There is None
Explanation:
This is because it is a derived function dependent on other factors.
A coefficient is a whole number that appears before the formula in an equation.
➡ ANSWER
☑ <em><u>C</u></em><em><u>.</u></em><em><u> </u></em><em><u>3.5 105</u></em><em><u> </u></em><em><u>Hz</u></em>