You must know the concentration of the acetic acid. Suppose the concentration is 0.1 M. The solution is as follows:
CH₃COOH → CH₃COO⁻ + H⁺
I 0.1 0 0
C -x +x +x
E 0.1 - x x x
Ka = (x)(x)/(0.1 - x)
1.8×10⁻⁵ = x²/(0.1 - x)
Solving for x,
x = 1.333×10⁻³ = H⁺
pH = -log[H⁺] = -log(1.333×10⁻³)
pH = 2.88
Answer:
Thats all i can think of Hope this helped
Explanation:
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Answer:
Poop
Explanation:everyone like poop
I THINK it's <span>1,1-Difluorononane, or </span>
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It's the other name of Water and it's formula would be H2O
