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Tatiana [17]
3 years ago
10

Factory in Seattle Seattle’s factory is the company’s newest. It was constructed with sustainable building techniques and materi

als, so its cost structure has been affected in several ways. The Seattle plant uses a mix of solar power (not very reliable with so many clouds), thermal power, and wind. It has an array of batteries, so at the beginning of each production day, there is “free” stored energy that can produce up to 8,000 units. Of course, energy is just one factor of the cost of production, but it is significant. The cost function for the Seattle factory is given by the following piecewise function. That is, is the cost function, where is the number of units produced. The plant’s maximum capacity is 42,000 units per day. Sketch a graph to model Seattle’s cost structure over the domain [0, 42000]. Be sure to label the axes and any endpoints where the graph breaks. (5 points) Describe the function over each part of its domain. State whether it is constant, increasing, or decreasing, and state the slope over each part. (5 points) Factory in Omaha Omaha’s factory has yet another type of cost structure. Its cost function is provided graphically. Its maximum capacity is 38,000 units per day.
Sketch a graph to model Seattle’s cost structure over the domain [0, 42000]. Be sure to label the axes and any endpoints where the graph breaks. (5 points)

Mathematics
2 answers:
Umnica [9.8K]3 years ago
8 0

Answer:

b. Describe the function over each part of its domain.  State whether it is constant, increasing, or decreasing, and state the slope over each part. (5 points)

Step-by-step explanation:

can someone do that one 2?

bulgar [2K]3 years ago
4 0
The answer would be this graph (see attached photo)

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well, first off let's check those two points, we know it's centerd at (-26 , 120) and we also know it passes through (0 , 0), so the distance between those two points is its radius

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{-26}~,~\stackrel{y_2}{120})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{(~~-26 - 0~~)^2 + (~~120 - 0~~)^2} \implies r=\sqrt{(-26)^2 + (120 )^2} \\\\\\ r=\sqrt{( -26 )^2 + ( 120 )^2} \implies r=\sqrt{ 676 + 14400 } \implies r=\sqrt{ 15076 } \\\\[-0.35em] ~\dotfill

\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-26}{h}~~,~~\underset{120}{k})}\qquad \stackrel{radius}{\underset{\sqrt{15076}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-26) ~~ )^2 ~~ + ~~ ( ~~ y-120 ~~ )^2~~ = ~~(\sqrt{15076})^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (x+26)^2+(y-120)^2 = 15076~\hfill

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Answer:

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Step-by-step explanation:

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The equation would be something like this:
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then simplify
y=72.39+.24x
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