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3 years ago

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I need this by today it’s due 4-24-20

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dybincka [34]3 years ago

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Answer:

Question 6

Plants use flowers to absorb photsynthese

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Which statement best describes why carbon can form a wide variety of organic compounds?

marishachu [46]

Carbon can form a wide variety of organic compounds because:

Each carbon atom covalently bonds with toms of carbon, hydrogen oxygen, and nitrogen

A carbon atom can have 4 single valence electrons around it. This allows it to form covalent bonds with many different atoms.

7 0

3 years ago

Read 2 more answers

Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO

Irina-Kira [14]

Answer : The enthalpy of formation of $H_2SO_4$ is, -812.4 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of $H_2SO_4$ will be,

$S+H_2+2O_2\rightarrow H_2SO_4$ $\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

(1) $S+O_2\rightarrow SO_2$ $\Delta H_1=-298.2$

(2) $SO_2+\frac{1}{2}O_2\rightarrow SO_3$ $\Delta H_2=-98.2$

(3) $SO_3+H_2O\rightarrow H_2SO_4$ $\Delta H_3=-130.2$

(4) $H_2+\frac{1}{2}O_2\rightarrow H_2O$ $\Delta H_4=-285.8$

Now adding all the equations, we get the expression for enthalpy of formation of $H_2SO_4$ will be,

$\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4$

$\Delta H=(-298.2)+(-98.2)+(-130.2)+(-285.8)$

$\Delta H=-812.4kJ/mol$

Therefore, the enthalpy of formation of $H_2SO_4$ is, -812.4 kJ/mole

3 0

3 years ago

How many mL of a 4.50 (m/v)% solution would contain 23.0 g of solute?

nlexa [21]

23.0 g/ (4.50 g/ mL) gives 5.11 mL as the volume.

4 0

3 years ago

Read 2 more answers

ethylene glycol, commonly used in automobile antifreeze, contains only carbon, hydrogen and oxygen.combustion analysis of a 23.4

Kay [80]

Answer:

Molecular formula of ethylene glycol is C₂H₆O₂.

Explanation:

Given data:

mass of ethylene glycol = 23.4 mg

mass of water = 20.42 mg

mass of carbon dioxide = 33.27 mg

molar mass of ethylene glycol = 62.0 g / mol

Molecular formula of ethylene glycol = ?

Solution:

percentage of carbon = (33.27 mg/ 23.46 mg) × (12 /44) × 100

= (1.4182× 0.27) × 100 = 38.29

percentage of hydrogen = (20.42 mg/ 23.46 mg) × (2 /18) × 100

= (0.8704× 0.11) × 100 = 9.67

percentage of oxygen = 100 - (38.29 + 9.67 )

= 100 - 47.96 = 52.04

Now we will determine the number of grams atoms of carbon, hydrogen and oxygen.

No. of gram atoms of carbon = 38.29 /12 = 3.19

No. of gram atoms of hydrogen = 9.67 / 1 = 9.67

No. of gram atoms of oxygen = 52.04 / 16 = 3.25

Atomic ratio:

C :H :O 3.19/ 3.19 : 9.67 / 3.19 : 3.25 /3.19

C :H :O 1 : 3 : 1

Molecular formula:

Molecular formula = n × (empirical formula)

n = molar mass of compound / empirical formula mass

empirical formula mass= 1 × 12 + 3 × 1 + 1 × 16

empirical formula mass= 12+3 +16 = 31

n = 62 g /mol / 31 = 2

Molecular formula = n × (empirical formula)

Molecular formula = 2 × (CH₃O)

Molecular formula = C₂H₆O₂

6 0

3 years ago

How many atoms are in 1 mole of hydrogen

Angelina_Jolie [31]

There are TWO atoms in one molecule of hydrogen.

8 0

3 years ago