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Sonja [21]
3 years ago
14

How did Thomson measure the charge to mass ratio of the electron? a.He shot helium nuclei into gold foil to measure the nuclei s

cattering against electrons within. b.He passed cathode rays through a magnetic field and measured the deflection. c.He suspended a drop of oil between electrodes to measure the electric field from the electrons. d. He measured very precisely a known quantity of hydrogen atoms and calculated the reduced mass ratio within each atom.
Chemistry
1 answer:
Ket [755]3 years ago
3 0

Answer:

The correct answer is option b. "He passed cathode rays through a magnetic field and measured the deflection".

Explanation:

J. J. Thomson was a notorious scientist that did not only made the discovery of the electron, but he measure its charge to mass ratio. In order to determine this property, Thomson passed cathode rays through a magnetic field and measured the deflection. Cathode rays are actually composed of particles, which are now known as electrons, and its charge to mass ratio is about 10^8 coulomb per gram.

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Nataliya [291]

The daughter isotope  : Radon-222 (Rn-222).

<h3>Further explanation</h3>

Given

Radium (Ra-226) undergoes an  alpha decay

Required

The daughter nuclide

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

The decay reaction uses the principle: the sum of the atomic number and mass number before and after decay are the same

Radium (Ra-226) : ₈₈²²⁶Ra

Alpha particles : ₂⁴He

So Radon-226 emits alpha α particles ₂He⁴  , so the atomic number decreases by 2, mass number decreases by 4

The reaction :

₈₈²²⁶Ra ⇒ ₂⁴He + ₈₆²²²Rn

4 0
3 years ago
How a mineral's chemical make-up looks like?
sveticcg [70]
You would have to go to sephora and check it out 
5 0
3 years ago
What is the empirical formula for a compound that is 29.44\% calcium, 23.55% sulfur, and 47.01% oxygen? This compound is a commo
PSYCHO15rus [73]

Answer:

Empirical formula is CaSO₄.

Explanation:

Given data:

Percentage of calcium =29.44%

Percentage of sulfur = 23.55%

Percentage of oxygen = 47.01%

Empirical formula = ?

Solution:

Number of gram atoms of Ca = 29.44 / 40 = 0.74

Number of gram atoms of S = 23.55 / 32 = 0.74

Number of gram atoms of O = 47.01 / 16 = 3

Atomic ratio:

            Ca                      :        S                :         O

           0.74/0.74           :     0.74/0.74      :       3/0.74

               1                     :          1              :          4

Ca : S : O = 1 : 1 : 4

Empirical formula is CaSO₄.

3 0
3 years ago
For the reaction A(g)
zubka84 [21]

Answer:

Yes

Explanation:

By definition, the equilibrium constanct, Kc, for the reaction A ⇒ 2B is

= [A]^1 / [B]^2

Substitute [A] = 4 and [B] = 2 in the equation,

[A]^1 / [B]^2

= 4^1 / 2^2

= 1

= Kc

So yes the reaction is at equilibrium.

6 0
2 years ago
NaOH (aq) + HCl(aq) H2O + NaCl (aq)
yuradex [85]

Answer:

The answer to your question is 0.005

Explanation:

Data

Volume of NaOH = 25 ml

[NaOH] = 0.2 M

moles of NaOH = ?

To solve this problem is not necessary to have the chemical reaction. Just use the formula of Molarity and solve it for moles.

Formula

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Convert volume to liters

          1000 ml ---------------- 1 l

              25 ml ---------------- x

               x = (25 x 1) / 1000

               x = 0.025 l

-Substitution

moles = 0.2 x 0.025

-Result

moles = 0.005

7 0
3 years ago
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