How did Thomson measure the charge to mass ratio of the electron? a.He shot helium nuclei into gold foil to measure the nuclei s
cattering against electrons within. b.He passed cathode rays through a magnetic field and measured the deflection. c.He suspended a drop of oil between electrodes to measure the electric field from the electrons. d. He measured very precisely a known quantity of hydrogen atoms and calculated the reduced mass ratio within each atom.
The correct answer is option b. "He passed cathode rays through a magnetic field and measured the deflection".
Explanation:
J. J. Thomson was a notorious scientist that did not only made the discovery of the electron, but he measure its charge to mass ratio. In order to determine this property, Thomson passed cathode rays through a magnetic field and measured the deflection. Cathode rays are actually composed of particles, which are now known as electrons, and its charge to mass ratio is about 10^8 coulomb per gram.
C. This is because the water has undergone a physical change meaning that the effects can be reversed. If nothing was added or lost from the water the ice would be the exact same weight.
Each column is called a group<span>. The elements in each </span>group have<span> the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons.</span>
The law of the conservation of mass states that matter is neither created nor destroyed, only converted to other forms. Therefore, the mass never changes, even if its appearance does.
