What is the molar ratio for the following equation after it has been properly balanced?
1 answer:
You might be interested in
Answer :
(a) The mass of produced is, 15.2 grams.
(b) The percent yield of the reaction is, 72.5 %
Explanation :
Part (a) :
Given,
Mass of = 85.1 g
Molar mass of = 27 g/mol
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 4 moles of react to give 2 moles of
So, 3.15 moles of react to give
mole of
Now we have to calculate the mass of
Molar mass of = 102 g/mole
Therefore, the mass of produced is, 161.2 grams.
Part (b) :
Now we have to calculate the percent yield of the reaction.
Experimental yield = 116.9 g
Theoretical yield = 161.2 g
Now put all the given values in this formula, we get:
Therefore, the percent yield of the reaction is, 72.5 %