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kotykmax [81]
3 years ago
15

(50 POINTS AND WILL GIVE BRAINLY!) which actions will help a package of hot chocolate powder to dissolve more quickly?

Chemistry
1 answer:
musickatia [10]3 years ago
3 0

A , i think because pure water won't dissolve the powder fast.

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How many atoms in total are there in 7.35 mol of magnesium oxide (MgO)<br> molecules?
andreev551 [17]

Answer:

4.42 x 10^24

Explanation:

3 0
3 years ago
How many kilocalories of heat are released when 75 g of steam at 100 degrees Celsius is converted to ice at 0 degrees Celsius?
VikaD [51]

Answer:

∴ Q = -7.52kCal

Explanation:

Using the formula for specific heat capacity:

Q = mcΔT

where ΔT = change in temperature (final - initial)  = (0 - 100)°C = -100°C

m = mass (g) = 75g

c = specific heat capacity = 4.2 J/g°C in water

⇒ Q = 75 × 4.2 × -100

= -31,500J

But 1J - 0.000239kCal

<u>∴ Q = -7.52kCal</u>

<u />

Let me know if I can be of further assistance.

5 0
3 years ago
Cobalt-60 is a strong gamma emitter that has a half- life of 5.26 yr. The co balt-60 in a radiotherapy unit must be replaced whe
Alenkasestr [34]

<u>Answer:</u> The sample of Cobalt-60 isotope must be replaced in January 2027

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = 5.26 years

Putting values in above equation, we get:

k=\frac{0.693}{5.26yrs}=0.132yrs^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 0.132yr^{-1}

t = time taken for decay process = ? yr

[A_o] = initial amount of the sample = 100 grams

[A] = amount left after decay process =  (100 - 75) = 25 grams

Putting values in above equation, we get:

0.132=\frac{2.303}{t}\log\frac{100}{25}\\\\t=10.5yrs

The original sample was purchased in June 2016

As, June is the 6th month of the year, which means the time period will be 2016+\frac{6}{12}=2016.5

Adding the time in the original time period, we get:

2016.5+10.5=2027

Hence, the sample of Cobalt-60 isotope must be replaced in January 2027

3 0
3 years ago
Help plz! im not understanding
valina [46]

a is 8.46 × 10^5

b is 3 ×10^-2

Explanation:

i hope this helps

4 0
2 years ago
If a gas occupies a volume of 950 mL at standard temperature, what volume will it
n200080 [17]
Voulme 1= 950 mL
Volume 2= ?
Temperature 1 = 25 C
Temperature 2 = 50 C
Convert your temperature to Kelvin
C+273=K
Temperature 1 = 25 C + 273 = 298 K
Temperature 2 = 50 C + 273 = 323 K

Plug in to the Formula
950 mL/298 K = ? / 323 K

Rearrange the formula to make one to solve for what is missing.
To get 323 K out of the denominator multiply by it.
Making it
950 mL x 323 K / 298 K = ?

Plug it in
950 mL x 323 K / 298 K = 1027.9 mL
3 0
2 years ago
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