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olga2289 [7]
4 years ago
9

Gas molecules are constantly in motion. True or False?

Chemistry
1 answer:
SpyIntel [72]4 years ago
4 0
True gas moves throughout the atmosphere
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Though Neon is a relatively small atom with a relatively high nuclear charge, it is difficult to add an electron to a neon atom.
Feliz [49]

Answer:

hjghjkhjkkhgjh

Explanation:

5 0
3 years ago
Two examples of organic chemical
spayn [35]

Answer:

there are literally millions - alkanes, alkenes, alkynes, alcohols, esters, carboxylic acids... to name but a few.

Explanation:

6 0
3 years ago
Balance the equation for magnasuin and oxygen to yield magnasuimoxide
Minchanka [31]

Answer:

2Mg + O₂  →  2MgO

Explanation:

Chemical equation:

Mg + O₂  →  MgO

Balanced chemical equation:

2Mg + O₂  →  2MgO

The balanced equation s given above and it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Steps to balanced the equation:

Step 1:

Mg + O₂  →  MgO

Mg = 1         Mg = 1

O = 2           O = 1

Step 2:

2Mg + O₂  →  MgO

Mg = 2         Mg = 1

O = 2           O = 1

Step 3:

2Mg + O₂  →  2MgO

Mg = 2         Mg = 2

O = 2           O = 2

6 0
3 years ago
Where do you write salt and suger why​
Rashid [163]

Answer:

here: "salt and sugar"

Explanation:

I dunno, looks pretty, gives 5 points. even tough any context is missing

but seriously:

salt and sugar look the same. just someone with a split personality

7 0
3 years ago
If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol
igomit [66]

Answer:

\Delta _RH=4x10^{-3}\frac{kJ}{mol}

Explanation:

Hello,

In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}

Best regards.

5 0
3 years ago
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