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4 years ago

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A square steel bar has a length of 8.4 ft and a 2.1 in by 2.1 in cross section and is subjected to axial tension. The final leng

th is 8.40392 ft . The final side length is 2.09967 in . What is Poisson's ratio for the material

1 answer:

nikitadnepr [17]4 years ago

6 0

Answer:

Poissons ratio = -0.3367

Explanation:

Poissons ratio = Lateral Strain / Longitudinal Strain

In this case, the longitudinal strain will be:

Strain (longitudinal) = Change in length / total length

Strain (longitudinal) = (8.40392 - 8.4) / 8.4

Strain (longitudinal) = 4.666 * 10^(-4)

While the lateral strain will be:

Strain (Lateral) = Change in length / total length

Strain (Lateral) = (2.09967 - 2.1) / 2.1

Strain (Lateral) = -1.571 * 10^(-4)

Solving the poisson equation at the top we get:

Poissons ratio = -1.571 / 4.666 <u>( 10^(-4) cancels out )</u>

Poissons ratio = -0.3367

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Using the data in the photo write the complex waveform expression

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Answer:

1st Harmonic:

$v(t) = 50\cos(2000\pi t)$

3rd Harmonic:

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5th Harmonic:

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7th Harmonic:

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The general form to represent a complex sinusoidal waveform is given by

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Where A is the amplitude in volts of the sinusoidal waveform

Where f is the frequency in cycles per second (Hz) of the sinusoidal waveform

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1st Harmonic:

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We have A = 9, f = 3000 and φ = 0

$v(t) = 9\cos(2\pi 3000 t + 0) \\\\v(t) = 9\cos(6000\pi t)$

5th Harmonic:

We have A = 6, f = 5000 and φ = 0

$v(t) = 6\cos(2\pi 5000 t + 0) \\\\v(t) = 6\cos(10000\pi t)$

7th Harmonic:

We have A = 2, f = 7000 and φ = 0

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Note: The even-numbered harmonics have 0 amplitude that is why they are not shown here.

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4 years ago

Read 2 more answers

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Given spring mass system will be in simple harmonic motion.We know that in simple harmonic motion the natural frequency given as follows

$\omega _n=\sqrt{\dfrac{K}{m}}$

Now by putting the values

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The equation of SHM given as

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The equation of motion will be

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3 years ago

A compressed-air drill requires an air supply of 0.25 kg/s at gauge pressure of 650 kPa at the drill. The hose from the air comp

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$L = \frac{(P_1-P_2) 2D}{\rho f v^2}$

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L = 46.35 m

5 0

3 years ago