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Dmitriy789 [7]
4 years ago
5

Write a function "funthree" that will print a box of characters. The function will always receive as the first input argument th

e character to print. If there are only two input arguments, they will be the character followed by a number, which is the number of rows and columns of the box to print. If, however, there are three input arguments, they will be the character, the number of rows, and the number of columns for the box of characters. Here are examples of calling the function:
Engineering
1 answer:
stiv31 [10]4 years ago
4 0

Answer: i8g7ieusgr7eytuu7esieso87 sugr7pi8y8hiuh9yehroe998 rydyh9 t9ry9 7 fdgerje 78re87es 7yehr87ehtu9hu7b puuhihugogi;ghi uhugyug fhglhfu fufbiup hughghuihu fhuihihiuhg uhfuhuig8fguh hguihfhjliigihfuhf;gjihgh hfuyt8uyiiohiodohi

Explanation: so first you are going to hyigfgegidii9thdf5dh8yy7 gdiuigp 87hgiuf 8yhijh gihoighhgd

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3. Assertive communication means:
natta225 [31]

Answer:

A. Confidently and directly communicating what you think and feel, without being aggressive or passive.

Explanation:

Assertive communication is the ability to express both positive and negative ideas in a way that it is a honest and direct message. It doesn't mean to say things to the other person with the intent of causing harm or making them feel better, it's just saying things as they are.

7 0
2 years ago
A tensile test was made on a tensile specimen, with a cylindrical gage section which had a diameter of 10 mm, and a length of 40
tamaranim1 [39]

Answer:

The answers are as follow:

a) 10 mm

b) 12.730 N/mm^{2}

c) 127.307 N/mm^{2}

d) 0.25

Explanation:

d1 = 10mm , L1 = 40 mm, L2 = 50 mm, reduction in area = 90% = 0.9

Force = F =1000 N

let us find initial area first, A1 = pi*r^{2} = 78.55 mm^{2}

using reduction in area formula : 0.9 = (A1 - A2 ) / A1

solving it will give,  A2 = 0.1 A1 = 7.855  mm^{2}

a) The specimen elongation is final length - initial length

50 - 40 = 10 mm

b) Engineering stress uses the original area for all stress calculations,

Engineering stress = force / original area  = F / A1 = 1000 / 78.55  

Engineering stress = 12.730 N / mm^{2}

c) True stress uses instantaneous area during stress calculations,

True fracture stress = force / final  area  = F / A2 = 1000 / 7.855

True Fracture stress = 127.30 N / mm^{2}

e) strain = change in length / original length

strain = 10 / 40  = 0.25

8 0
3 years ago
The art of manipulating, influencing, or deceiving you into taking some action that isn’t in your best interest or in the best i
Mrac [35]
Social engineering is the answer
7 0
2 years ago
Pam Jones worked for 41 years at the same company and had positive performance ratings and personnel records. She needed a calcu
UNO [17]

Answer:

a) The key issues are the sue for libel and the evidence.

b) I would make a deal with her and implement a security program in the company.

Explanation:

The main issue in this case is that Pam Jones sued the company for libel, and the company remains in a position in which it has to prove that the internal investigation followed the right steps and indeed, the proves reflected that she was guilty and the fact that she got fired was correct.

The important here is exactly that the theft can be proved.

As an HR Director, I would give the correct proves in order to win the case, and if that is impossible, because of the tools and evidence, I would make a deal with her where both parts can be adequate to the problem.

She can´t be working again in the company but she can get financed according to her working years; also I would use this case as a growing opportunity by implementing new security methods that give more confidence between the company and its employees.

5 0
3 years ago
A cylindrical drill with radius 4 is used to bore a hole through the center of a sphere of radius 5. Find the volume of the ring
ANTONII [103]

Answer:

The volume of the ring shaped solid that remains is 21 unit^3.

Explanation:

The total volume of the sphere is given as:

Volume of Sphere = (4/3)πr^3

where, r = radius of sphere

Volume of Sphere = (4/3)(π)(5)^3

Volume of Sphere = 523.6 unit^3

Now, we find the volume of sphere removed by the drill:

Volume removed = (Cross-sectional Area of drill)(Diameter of Sphere)

Volume removed = (πr²)(D)

where, r = radius of drill = 4

D = diameter of sphere = 2*5 = 10

Therefore,

Volume removed = (π)(4)²(10)

Volume removed = 502.6 unit^3

Therefore, the volume of ring shaped solid that remains will be the difference between the total volume of sphere, and the volume removed.

Volume of Ring = Volume of Sphere - Volume removed

Volume of Ring = 523.6 - 502.6

<u>Volume of Ring = 21 unit^3</u>

5 0
3 years ago
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