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3 years ago

What will happen to the gas pressure as the temperature increases, if the amount and volume of the gas are kept constant?

Chemistry

1 answer:

mr_godi [17]3 years ago

5 0

P1/P2=T1/T2, so as the temperature increases pressure increases

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2 years ago

BRAINLIEST TO FIRST CORRECT ANSWER, THANKS!

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Answer:

increased

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3 years ago

What is the correct equation for the reaction quotient of the following reaction? 2Fe3+(aq) + Zn(s) ⇌ 2Fe2+(aq) + Zn2+(aq)

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Explanation:

A reaction quotient is defined as the ratio of concentration of products over reactants raised to the power of their stoichiometric coefficients.

A reaction quotient is denoted by the symbol Q.

For example, $2Fe^{3+}(aq) + Zn(s) \rightleftharpoons 2Fe^{2+}(aq) + Zn^{2+}(aq)$

The reaction quotient for this reaction is as follows.

Q = $\frac{[Fe^{2+}]^{2}[Zn^{2+}]}{[Fe^{3+}]^{2}}$

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3 years ago

List a mixture that can be separated by fractional distillation

vivado [14]

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3 years ago

A sample of oxygen gas has a volume of 3.24 L at 29°C. What volume will it occupy at 104°C if the pressure and number of mol are

ohaa [14]

<u>Answer:</u> The final volume of the oxygen gas is 4.04 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=3.24L\\T_1=29^oC=(29+273)K=302K\\V_2=?\\T_2=104^oC=(104+273)K=377K$

Putting values in above equation, we get:

$\frac{3.24L}{302K}=\frac{V_2}{377K}\\\\V_2=4.04L$

Hence, the final volume of the oxygen gas is 4.04 L

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3 years ago