False
Explanation:
Electron affinity is negative when energy is absorbed and it is positive when energy is released.
Electron affinity is defined as the energy released in adding an electron to a neutral atom in the gas phase.
It is a measure of the readiness of an atom to gain an electron.
In a reaction where energy is released, electron affinity is usually positive. These reactions are called exothermic reactions.
Endothermic reactions in which energy is absorbed have negative electron affinity values.
Learn more:
Endothermic reactions brainly.com/question/12964401
#learnwithBrainly
Answer:
Initial rate of the reaction when concentration of hydrogen gas is doubled will be 
.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
Initial rate of the reaction = R = 
![R = k\times [N_2][H_2]^3](https://tex.z-dn.net/?f=R%20%3D%20k%5Ctimes%20%5BN_2%5D%5BH_2%5D%5E3)
![4.0\times 10^5 M/s=k\times [N_2][H_2]^3](https://tex.z-dn.net/?f=4.0%5Ctimes%2010%5E5%20M%2Fs%3Dk%5Ctimes%20%5BN_2%5D%5BH_2%5D%5E3)
The initial rate of the reaction when concentration of hydrogen gas is doubled : R'
![[H_2]'=2[H_2]](https://tex.z-dn.net/?f=%5BH_2%5D%27%3D2%5BH_2%5D)
![R'=k\times [N_2][H_2]'^3=k\times [N_2][2H_2]^3](https://tex.z-dn.net/?f=R%27%3Dk%5Ctimes%20%5BN_2%5D%5BH_2%5D%27%5E3%3Dk%5Ctimes%20%5BN_2%5D%5B2H_2%5D%5E3)
![R'=8\times k\times [N_2][H_2]^3](https://tex.z-dn.net/?f=R%27%3D8%5Ctimes%20k%5Ctimes%20%5BN_2%5D%5BH_2%5D%5E3)
Initial rate of the reaction when concentration of hydrogen gas is doubled will be .
Yes..? I don’t understand what you’re trying to ask mate.
The calculation for such a question can be achieved via Avogadro hypothesis
We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms
Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..
44g/mole = 6.023 ※10^23 CO2 molecules
=> 1g = (6.023/44) ※10^23 CO2 molecules
==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….
Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g
if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
