What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total vol

Question

3 years ago

14

ume of 2.40 liters?
0.104 M NaOH
0.201 M NaOH
0.361 M NaOH
0.412 M NaOH

2 answers:

skelet666 [1.2K] · Answer 1 · 2022-01-21T17:44:25+03:00

6 0

Answer:

=0.104 M of NaOH

Explanation:

NaOH=23+16+1=40

40=1 M

10=? And the answer is 0.25

0.25=2400

? =1000

1000*0.25/2400=0.104

ivann1987 [24] · Answer 2 · 2022-01-21T16:02:52+03:00

Answer:

0.104 M NaOH

Explanation:

molarity or concentration is the number of moles of solute dissolved in 1 L of solution

the mass of NaOH dissolved is 10.0 g

therefore number of moles of NaOH is - 10.0 g / 40 g/mol = 0.25 mol

molarity/concentration = number of moles of solute / volume of solution

substituting the values in the equation = 0.25 mol / 2.40 L = 0.104 mol/L

therefore molarity of NaOH is 0.104 M