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3 years ago

Gases Test Chemistry

Chemistry

1 answer:

Soloha48 [4]3 years ago

4 0

Answer:

6.64 l is the answer.......

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Calculate the Ka for the following acid. Determine if it is a strong or weak acid. HClO2(aq) dissolves in aqueous solution to fo

Talja [164]

Answer:

The value of Ka $= 1.1*10^{-2}$

It is a weak acid

Explanation:

From the question we are told that

The concentration of $[HClO_2]=0.24M$

The concentration of $[H^+]=0.051M$

The concentration of $[ClO_2^-]=0.051M$

Generally the equation for the ionic dissociation of $HClO_2$ is

$HClO_2_(aq) -------> H^{+}_{(aq)} + ClO_2^{-}_{(aq)}$

The equilibrium constant is mathematically represented as

$Ka = \frac{concentration \ of \ product }{concentration \ of \ reactant }$

$= \frac{[H^+][ClO_2^-]}{[HClO_2]}$

Substituting values since all value of concentration are at equilibrium

$Ka = \frac{0.051 * 0.051}{0.24}$

$= 1.1*10^{-2}$

Since the value of is less than 1 it show that in water it dose not completely

disassociated so it an acid that is weak

3 0

3 years ago

Pls help with science

MissTica

The answer is C because it is believed that those two were once connected

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3 years ago

A single 250 gram

Gala2k [10]

2.2 x 10^-2

0.055 / 250 = 0.00022 - This would be 2.2 x 10^-4, but the question is asking for percent, not proportion, so multiply by 100% to get the percentage.

0.00022 * 100% = 0.022% = 2.2 * 10^-2

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What is biodiversity? I don't really understand...

Vesnalui [34]

Answer:

it is also know as biological diversity

Explanation:

it refers to the varieties or various forms of plants and animals species

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An 80g sample of 3 1 H decays, leaving 2.5g of 3 1 H.

RUDIKE [14]

Here is the link to the answer:

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