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bonufazy [111]
3 years ago
10

Help me please!!!!!!!!?????

Chemistry
1 answer:
kirill [66]3 years ago
4 0

Answer:

i believe its A or D

Explanation:

sorry is its wrong

hope it helps

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The lightest weight element that is not a gas
LUCKY_DIMON [66]

Answer:Lithium

Explanation:Lithium has 3 protons, and 4 neutrons making it the lightest element that isn't a gas.

5 0
3 years ago
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Please give me a clear message on what to do.<br> how do you change your brainly username?
emmainna [20.7K]

Answer:

you can't change it mate I am so sorry

BTW can you help me in my latest questions it's not related to studies it's a problem I am having with my laptop that need to get cured as I have exam tomorrow

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A balloon full of air has a volume of 1.00L at a temperature of 23 °C. What is the balloon's volume at 33°C?
igomit [66]

Answer:

V2= 1.03L

Explanation:

Start off with what you are given.

V^1: 1.00L

T^1: 23°C

V^2?

T^2: 33°C

If you know your gas laws, you have to utilise a certain gas law called Charles' Law:

V^1/T^1 = V^2/T^2

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

(23+273 = 296)     (33+273 = 306)

Multiply crisscross

1.00/296= V^2/306

296V^2 = 306

Dividing both sides by 296 to isolate V2, we get

306/296 = 1.0337837837837837837837837837838

V2= 1.03L

5 0
3 years ago
Which best describes a compound such as sodium chloride?
finlep [7]

Answer:

It s a pure substance.

Explanation:

Can only be separated into its different elements by chemical means because it is connected by a chemical bond.

4 0
3 years ago
Bromine monochloride is synthesized using the reaction:
Sergeu [11.5K]

Answer:

11.72 grams

Explanation:

Let the equilibrium concentration of BrCl be y

Initial concentration of Br2 = number of moles ÷ volume = (0.979×1000/160) ÷ 199 = 0.031 M

Initial concentration of Cl2 = (1.075×1000/71) ÷ 199 = 0.076 M

From the equation of reaction

1 mole of Br2 reacted with 1 mole of Cl2 to form 2 moles of BrCl

Therefore, equilibrium concentration of Br2 = (0.031 - 0.5y) M while that of Cl2 = (0.076 - 0.5y) M

Kp = [BrCl]^2/[Br2][Cl2]

1.1×10^-4 = y^2/(0.031 - 0.5y)(0.076 - 0.5y)

y^2/0.002356-0.0535y+0.25y^2 = 0.00011

y^2/0.00011 = 0.002356-0.0536y+0.25y^2

9090.9y^2-0.25y^2+0.0536y-0.002356 = 0

9090.65y^2+0.0535y-0.002356 = 0

The value of y must be positive and is obtained using the quadratic formula

y = [-0.0535 + sqrt(0.0535^2 - 4×9090.65×-0.002356)] ÷ 2(9090.65) = 9.2025/18181.3 = 0.00051 M

Mass of BrCl = concentration×volume×MW = 0.00051×199×115.5 = 11.72 grams

4 0
3 years ago
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