How many different committees can be formed from 8 teachers and 48 students if the committee consists of 3 teachers and 4 stude
2 answers:
Since we don't care about the order in which we select people, we will use the combinatoric approach, rather than permutations.
Since we want to select 3 teachers from a total of 8, this is the notation to select 3 teachers from 8 (objects).
Teachers :
Similarly, students :
Now, since we want both at the same time, we will need to multiply both to yield your final answer:
different ways.
Since we want to select 3 teachers from a total of 8, this is the notation to select 3 teachers from 8 (objects).
Teachers :
Similarly, students :
Now, since we want both at the same time, we will need to multiply both to yield your final answer:
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Hi there! The answer is 0 solutions.
First we need to work out the parenthesis (for instance possible by using rainbow technique).
Now subtract 12.
Now we can see that the right side of the equation is always 8 smaller than the left side of the equation. Because the right is always smaller, this equation cannot be solved. Therefore there are no solutions to this equation. The answer is 0 solutions.
First we need to work out the parenthesis (for instance possible by using rainbow technique).
Now subtract 12.
Now we can see that the right side of the equation is always 8 smaller than the left side of the equation. Because the right is always smaller, this equation cannot be solved. Therefore there are no solutions to this equation. The answer is 0 solutions.