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lara31 [8.8K]
3 years ago
6

How many different committees can be formed from 8 teachers and 48 students if the committee consists of 3 teachers and 4 ​stude

nts?
Mathematics
2 answers:
valkas [14]3 years ago
6 0
As many as you'd like
drek231 [11]3 years ago
6 0
Since we don't care about the order in which we select people, we will use the combinatoric approach, rather than permutations.
Since we want to select 3 teachers from a total of 8, this is the notation to select 3 teachers from 8 (objects).

Teachers : ^{8}C_3
Similarly, students : ^{48}C_{4}

Now, since we want both at the same time, we will need to multiply both to yield your final answer: ^{8}C_3 \cdot ^{48}C_{4} = 10,896,480 different ways.
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