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lord [1]
3 years ago
12

Write an equivalent fraction for each whole number 6

Mathematics
1 answer:
Sidana [21]3 years ago
7 0
3/2 I'm pretty sure that's a correct answer
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Pls help I’ll give the big brain award or whatever
andre [41]

Answer:

2

1

-0

-1

-2

1

Step-by-step explanation:

300x80=24,000

7 0
3 years ago
Find the circumference of circle with a radius of 63mm. Use 22/7 for pi
Mariulka [41]

Answer:

396

Step-by-step explanation:

circumference of a circle is 2 x pi x r = 2 x 63 x (22/7) = 396

5 0
3 years ago
Read 2 more answers
There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit
DaniilM [7]

Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = nCr * p^{r} * q^{n-r}

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = 15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}

p(x=3) = 455 * 0.4^{3} * 0.6^{12}

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday  = 1 - 0.0633 = 0.9337

3 0
3 years ago
It will cost $5.50 per person attending and $25 to rent a location for a party.
olasank [31]
D = 5.5p + 25

D: dollars
P: people attending
4 0
2 years ago
3/2•6-3+5/3•3<br><br> anyone know this ?
Solnce55 [7]
I believe the answers is 11
3 0
3 years ago
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