Answer:
Real values of x where x < -1
Step-by-step explanation:
Above the x-axis, the function is positive.
The function is decreasing when the gradient is negative.
The function has a positive
coefficient, therefore the vertex is a local minimum;
This means the gradients are negative before the vertex and positive after it;
To meet the conditions therefore, the function must be before the vertex and above the x-axis;
This will be anywhere before the x-intercept at x = -1;
Hence it is when x < -1.
Step-by-step explanation:
x= -2,
(x - 5) / 2= -6
( (-2) - 5) / 2= -6
(-7) / 2 = -6
-3.5 = - 6
right hand side not equal to left hand side of this equation.so,x= -2 cannot exist for this equation.
x=2,
(x - 5) / 2= -6
(2 - 5) / 2= -6
(-3) / 2= -6
-1.5 = - 6
right hand side not equal to left hand side of this equation.so,x= 2 cannot exist for this equation.
x= -17
(x - 5) / 2= -6
( ( -17) - 5) / 2= -6
(- 22) / 2= -6
-11 = -6
right hand side not equal to left hand side of this equation.so,x= -17 cannot exist for this equation.
x= -7,
(x - 5) / 2= -6
( ( -7) -5) / 2= -6
(-12) / 2= -6
-6= -6
right hand side equal to left hand side of this equation.so,x= -7 exist for this equation.
Answer:
8w : 3.8974342 ≈ 3.9 or 4 (hope it help)
Step-by-step explanation:
1w : 2
2w : 2 + 10% = 2.2
3w : 2.2 + 10% = 2.42
4w : 2.42 + 10% = 2.662
5w : 2.662 + 10% = 2.9282
6w : 2.9282 + 10% = 3.22102
7w : 3.22102 + 10% = 3.543122
8w : 3.543122 + 10% = 3.8974342
3.8974342 ≈ 3.9 or 4
Answer:
To calculate the radius of a circle by using the circumference, take the circumference of the circle and divide it by 2 times π.
The two formulas that are useful for finding the radius of a circle are C=2*pi*r and A=pi*r^2.
The diameter is 2 times larger than the radius
Step-by-step explanation:
Hope this helped
:)
