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BabaBlast [244]
3 years ago
11

A wheel with a 19-inch diameter is turning at a rate of 33 revolutions per minute. To the nearest inch, what is the speed of the

point on the rim in in/min?
Mathematics
1 answer:
bagirrra123 [75]3 years ago
3 0
Convert 33 rev/min to rad/s then use w = v/r, solve for v, where v is the tangential velocity of the point. 
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WILL GIVE BRANLIEST! pls help thank u sm!! :-) u are all amazing
Andrews [41]

Answer:

C

Step-by-step explanation:

Given

3(x+9)^{\frac{3}{4} } = 24 ( divide both sides by 3 )

(x+9)^{\frac{3}{4} } = 8

Raise both sides to the power of \frac{4}{3}

x + 9 = 8^{\frac{4}{3} } = (\sqrt[3]{8}) ^{4} = 2^{4} = 16 ( subtract 9 from both sides )

x = 7 → C

5 0
3 years ago
in algebra, you can use function ________ to express the idea that salary depends on the number of hours of training.
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Four people have measured the height of a wall using different methods. Their results are shown in the table. Order their measur
slavikrds [6]

Answer:

5/2, 2.6, 1 + sqrt(3), sqrt(8)

Step-by-step explanation:

Use a calculator:

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Answer:

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3 0
3 years ago
What is 9^2+a= square root of 113 what is the value of a
sergiy2304 [10]
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5 0
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Example 2:
Montano1993 [528]
Taking this example into account, we can see that setting the first value equal to 1, we obtain that F(x)=0.5x+1=4 and x=6. Using this information, we find that F(x+1)=0.5(x+1)+1=0.5(6+1)+1=4.5. It shows that when x is positive, the succussive terms are increasing.

Referring to that finding, if we set initial value less than zero, which means that we are solving 0.5x+1<0 and taking a number in the interval of the solution, which means x ∈ (- ∞, -20). Setting x=-19, we find that F(x)=0.5x+1=-19 and x=-40. In the next iteration, F(x+1)=0.5(x+1)+1=0.5(1-40)+1=-18.5. In the next iteration, F(x+2)=0.5(x+2)+1=0.5(2-40)+1=-18. By this way, we find that even if the initial value is less than zero, value of the successive iterations is increasing. 

Using the function g(x)=-x+2 and taking the initial value equal to 4, we find that g(x)=-x+2=4 and x=-2. In the next iteration, g(x+1)=-(x+1)+2=-(-2+1)+2=3. If we continue the iterations we'll see that they are decreasing.
Setting the initial value equal to 2, we find that g(x)=-x+2=2 and x=0. The next iteration is g(x+1)=-(x+1)+2=1. In this case, the interations are also decreasing. 
If we set the initial value equal to 1, we find that g(x)=-x+2=1 and x=1. In the next iteration, g(x+1)=-(x+1)+2=0 and the iterations are decreasing. 
8 0
3 years ago
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