Answer: I am pretty sure it is (b) what is the value of mass suspended at the end of the spring.
Explanation:
Answer:
4N downward
Explanation:
the 16N left and right cancel each other out, so you are left with the 4N downward.
Answer:
A) F = 1.09 10 5 N, b) Yes
Explanation:
Part A
For this exercise we need the number of free electrons in copper, as the valence of copper +1 there is a free electron for each atom. Let's use the concept of density to find the mass of copper in the sphere
ρ = m / V
.m = ρ V = ρ 4/3 π r³
The radius is half the diameter
r = 1.9 10⁻² / 2 = 0.95 10⁻² m
ρ = 8960 kg / m3
m = 8960 4/3 π (0.95 10⁻²)³
m = 3.2179 10⁻² kg
The molecular weight of copper is 63,546 g / mol which has 6,022 10²³ atoms
With this we can use a rule of proportions to enter the number of atom is this mass
#_atom = 6.022 10²³ 3.2179 10⁻² / 63.546 10⁻³
#_atom = 3,049 10²³
Therefore there is the same number of electrons, as they indicate that the charge of the protone and the electon differs by 1/10⁹ the total charge for each spherical is
q = e / 10⁹ #_atom
q = e / 10⁹ 3,049 1023
q = 3,049 10⁴ (-1.6 10⁻¹⁹)
q = -4,878 10-5 C
Electric force is
F = k q₁q₂ / r²
F = k q² / r²
Let's calculate
F = 8.99 10⁹ (4.878 10⁻⁵)²2 / (1.4 10⁻²)²
F = 1.09 10 5 N
This is a force of repulsion.
Part B
The magnitude of this force is in very easy to detect
The 'formulas' to use are just the definitions of 'power' and 'work':
Power = (work done) / (time to do the work)
and
Work = (force) x (distance) .
Combine these into one. Take the definition of 'Work', and write it in place of 'work' in the definition of power.
Power = (force x distance) / (time)
From the sheet, we know the power, the distance, and the time. So we can use this one formula to find the force.
Power = (force x distance) / (time)
Multiply each side by (time): (Power) x (time) = (force) x (distance)
Divide each side by (distance): Force = (power x time) / (distance).
Look how neat, clean, and simple that is !
Force = (13.3 watts) x (3 seconds) / (4 meters)
Force = (13.3 x 3 / 4) (watt-seconds / meter)
Force = 39.9/4 (joules/meter)
<em>Force = 9.975 Newtons</em>
Is that awesome or what !
