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nika2105 [10]
2 years ago
11

Earth is about 93 million miles from the Sun but only 239,000 miles from the Moon. Likewise, the Sun has a mass that is over 20

million times that of the Moon. Earth experiences a strong gravitational attraction to both of these bodies, but for two different reasons. Using what you know about the factors that influence gravity, what specific characteristic or characteristics contribute to the attraction between Earth and the Moon? What specific characteristic or characteristics contribute to the attraction between Earth and the Sun?
Physics
1 answer:
Yakvenalex [24]2 years ago
7 0

Answer:

Gravity is dependent on the mass of two bodies and the distance between them. There is a strong gravitational attraction between Earth and the Moon because they’re relatively close to one another. There is a strong gravitational attraction between Earth and the Sun because the Sun is so massive

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A car travels 90 meters due north in 15 seconds. Then the car
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Perfect square of 11650​
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Answer:

Since the area of the perfect square is 11650, and all of a squares sides ar equal, we just need to find the square root.

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Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli
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Answer:

Therefore,

Final velocity of the coupled carts after the collision is

v_{f}=4\ m/s

Explanation:

Given:

Mass of  Glidding Cart = m₁ = 2 kg

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Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = v_{f}=?

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}

Substituting the values we get

2\times 14 + 5\times 0 =(2+5)\times v_{f}

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Therefore,

Final velocity of the coupled carts after the collision is

v_{f}=4\ m/s

8 0
3 years ago
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blsea [12.9K]

Answer:

Explanation:

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