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r-ruslan [8.4K]
3 years ago
14

If the dartboard below is used to model an atom, which subatomic particles would be located at Z? *

Physics
1 answer:
Anna11 [10]3 years ago
7 0

I know that protons and neutrons are located at the center of an atom, so the correct answer is D

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A storm is moving in quickly. The weather station reported that it is traveling west at 40 miles per hour. This information desc
Masteriza [31]
This information describes the storm's velocity.
8 0
3 years ago
What is your mass in kilograms?
SIZIF [17.4K]

Answer:

Take whatever you weigh in pounds and divide by 2.205.

Explanation:

Because weight is a measure of the force you exert on the earth, with some simple manipulation of Newton's second law we can get your mass in kilograms. 2.205 is just a nice constant that does that for you, but the more in-depth version is that

F = ma

The equation for weight is thus

W = mg, where W is your weight in pounds, m is your mass, and g is the acceleration due to gravity (9.80 m/s^2)

Thus, your mass in kilograms is m = W / g.

3 0
3 years ago
What If? The coil and applied magnetic field remain the same, but the circuit providing the current in the coil is now changed.
RUDIKE [14]

Answer:

Using equations

R will be 1.25 Kilo ohm

5 0
3 years ago
PLEASE HURTY FAT ON QUIZ ATM!!!! 25 POINTS!!!!!! A student pushes a 40-N walk across the floor for a distance of 10 m how much w
algol13
Work is force times distance, so W = 40 N * 10 m = 400 J
8 0
3 years ago
Hey any physicist or engineer around. am giving brainliest to anyone who will answer this question.
Oduvanchick [21]

Answer:

N = 167 Newtons

R = 727 Newtons

Explanation:

i) For static equilibrium, moments about any convenient point must sum to zero.

A moment is the product of a force and a moment arm length. Only the force acting perpendicular to a moment arm passing through the pivot point makes a moment.

ii) I will <em>ASSUME </em>the two moment arms are 0.05m and 0.15 m

CCW moments about the fulcrum are

190 N(0.2 m) + 280 N(0.05 m) = 52 N•m

CW moments are (N)N(0.15 m + 90 N(0.3 m) = 27 + 0.15N N•m

For static equilibrium, these must be equal

27 + 0.15N = 52

       0.15N = 25

              N = 166.6666666...

Sum moments about N to zero

(Same as saying CW and CCW moments must balance)

190(0.2 + 0.15) + 280(0.05 + 0.15) - R(0.15) - 90(0.3 - 0.15) = 0

R = 726.6666666...

We could verify this by summing vertical forces to zero.

R - 190 - 280 - 166.666666 - 90 = 0

R = 726.6666666...

8 0
3 years ago
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