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r-ruslan [8.4K]
3 years ago
14

If the dartboard below is used to model an atom, which subatomic particles would be located at Z? *

Physics
1 answer:
Anna11 [10]3 years ago
7 0

I know that protons and neutrons are located at the center of an atom, so the correct answer is D

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Find the equation of the line below.
Musya8 [376]

Answers all in picture below

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7 0
3 years ago
Correct Number Formats Numbers may be entered in several formats - including scientific notation and numerical expressions.
Illusion [34]

Answer:

a. Valid

b. Invalid

c. Invalid

d. Invalid

e. Valid

f.  Valid

g. Invalid

Explanation:

a.

Since, it follows all the four rules,

Therefore, this number is <u>Valid</u>

b.

It uses upper case E, instead of lower case e.

Therefore, it is <u>Invalid</u>

c.

It violates third rule for including unit.

Therefore, it is <u>Invalid</u>

d.

It violates the first rule. As, there is a space between 6 and e. While in the example given in question, there is no gap.

Therefore, it is <u>Invalid</u>

e.

Since, it follows all the four rules,

Therefore, this number is <u>Valid</u>

f.

Since, it follows all the four rules,

Therefore, this number is <u>Valid</u>

g.

It violates third rule for including unit.

Therefore, it is <u>Invalid</u>

6 0
3 years ago
Why is ice harder than liquid water?
yaroslaw [1]
Hello~ 

Ice is harder than liquid water because<span> the molecules of ice are linked more tightly together than the molecules of liquid water. 

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6 0
3 years ago
The Moon orbits Earth in an average of p = 27.3 days at an average distance of a =384,000 kilometers. Using Newton’s version of
Korvikt [17]

Answer:

The mass of the earth, M=6.023\times 10^{24}\ kg

Explanation:

It is given that,

Time taken by the moon to orbit the earth, T=27.3\ days=2358720\ m

Distance between moon and the earth,r=384000\ km=384\times 10^6\ m

We need to find the mass of the Earth using Kepler's third law of motion as :

T^2=\dfrac{4\pi^2}{GM}r^3

M=\dfrac{4\pi^2r^3}{T^2G}

M=\dfrac{4\pi^2\times (384\times 10^6)^3}{(2358720)^2\times 6.67\times 10^{-11}}

M=6.023\times 10^{24}\ kg

So, the mass of the earth is 6.023\times 10^{24}\ kg. Hence, this is the required solution.

7 0
3 years ago
Calculate the work done on a Pressure / Volume (PV) isothermal expansion where 400 Pa and 0.08 volume in m3?
Ainat [17]
PV = 400 x 0.08 = 32 J

Hope this helps
7 0
3 years ago
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