Answer:
Explanation:
In the x direction the force will be
½(-w₀)L/2 = -¼w₀L
acting ⅔(L/2) = L/3 below the x axis.
In the y direction the force will be
½(-w₀)L + ½w₀L/2 = -¼w₀L
the magnitude of the resultant will be
F = w₀L √((-¼)² + (-¼)²) = w₀L√⅛
in the direction
θ = arctan(-¼w₀L / -¼w₀L) = 225°
to find the distance, we balance moments
(w₀L√⅛)[d] = ½(w₀)L[⅔L] + ¼w₀L[⅔L/2] - ¼w₀L[L - ⅓L/2]
(√⅛)[d] = ½ [⅔L] + ¼ [⅔L/2] - ¼ [L - ⅓L/2]
(√⅛)[d] = ½[⅔L] + ¼[⅔L/2] - ¼[L - ⅓L/2]
(√⅛)[d] = ⅓L + ⅟₁₂L - ¼L + ⅟₂₄L
(√⅛)[d] = 5L/24
d = 5L/24 / (√⅛)
d = 5√⅛L/3
Answer: 5.79 s
Explanation:
Vs=0 m/s starting speed(from rest)
Vf=325 km/h= 325*1000/3600= 90.28 m/s
a=15.6m/s²
Using equation for acceleration we can find out time :
a=(Vf-Vs)/t
t=(Vf-Vs)/a
t=(90.28 m/s-0m/s)/15.6 m/s²
t=5.79 s
Answer:
Explanation:
Average velocity = Displacement/Time
ΔS = -10+6
ΔS = -4m
Given tme = 30s
Average velocity = -4/30
Average velocity = -0.13m/s
Average speed = Distance/Time
Total distance covered = 10m+6m
Total distance covered = 16m
Average speed = 16/30
Average speed = 0.53m/s
After the ball reaches the top and begins its return back down, it's just a falling object that's been dropped.
The amount that its downward speed increases every second is just the acceleration of gravity on Earth.
That's <em>9.81 meters per second</em> every second.
