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kykrilka [37]
3 years ago
12

When in orbit, a satellite such as the space shuttle is

Physics
2 answers:
My name is Ann [436]3 years ago
8 0
When in orbit, a satellite such as the space shuttle s <span>in non-accelerated motion. </span>
JulijaS [17]3 years ago
7 0

Answer: B

Explanation:

When in orbit, a satellite is hold in position thanks to, between others, the earth's gravity. So the C option is discarded.

A projectile is an object thrown by the exertion of some force, like a bullet or a cannonball.

A satellite is placed in some orbit, so he can rotate the earth. The movement of the satellite is non-accelerated motion, because the only forces that act on the satellite are the forces that hold him in orbit.

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Please need help with this
lutik1710 [3]

The first and third choices could both do it, but the first choice makes a much better, clear demonstration.

8 0
4 years ago
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A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 35 km/h at the 67-m mar
xz_007 [3.2K]

Answer:

0.705 m/s²

Explanation:

a) The sprinter accelerates uniformly from rest and reaches a top speed of 35 km/h at the 67-m mark.

Using newton's law of motion:

v² = u² + 2as

v = final velocity = 35 km/h = 9.72 m/s, u = initial velocity = 0 km/h,  s = distance = 67 m

9.72² = 0² + 2a(67)

134a = 94.484

a = 0.705 m/s²

b) The sprinter maintains this speed of 35 km/h for the next 88 meters. Therefore:

v = 35 km/h = 9.72 m/s, u = 35 km/h = 9.72 m/s, s = 88 m

v² = u² + 2as

9.72² = 9.72² + 2a(88)

176a = 9.72² - 9.72²

a = 0

c) During the last distance, the speed slows down from 35 km/h to 32 km/h.

u = 35 km/h = 9.72 m/s, v = 32 km/h = 8.89 m/s, s = 200 - (67 + 88) = 45 m

v² = u² + 2as

8.89² = 9.72² + 2a(45)

90a = 8.89² - 9.72²

90a = -15.4463

a = -0.1716 m/s²

The maximum acceleration is 0.705 m/s² which is from 0 to 67 m mark.

8 0
3 years ago
Pick a common happening , develop an explanation for it , and describe an experiment you could perform to test your explanation.
disa [49]
Plant's produce oxygen, to explain this you would state that the plant uses CO2 from the air and removes the carbon and then release breathable O2 into the atmosphere. To test this you could use a small fern and put it in a sealed container of some kind big enough to hold it, then add a burning candle in the container with the plant, since we know fire burms O2 and creates CO2 the plant should use the CO2 and create more O2 keeping the fire from burning out from lack of oxygen
5 0
3 years ago
An internal combustion engine uses fuel, of energy content 44.4 MJ/kg, at a rate of 5 kg/h. If the efficiency is 28%, determine
Fudgin [204]
Efficiency =  Power Output / Power Input

Power Input = Rate of Energy input = 44.4 MJ/kg * 5 kg/h

 = 222 MJ/h

But 1 hour = 3600seconds

222 MJ/h = 222 MJ/3600s =  0.061667 MW              J/s = Watts

Power input = 0.061667 MW = 61 667 W

From  Efficiency =  Power Output / Power Input

   28% =  Power Output / 61667

   Power Output = 0.28 * 61667

   Power Output = 17266.76 W
 
  Power Output = 17 267 W

 Rate of heat Rejection = Power input - Power output

                                        = 61667 - 17267 = 44400 W

Rate of heat Rejection = 44 400 W.


C- Copyright.
5 0
3 years ago
How many (whole number of) 91 kg people
Tcecarenko [31]

We are given that the maximum mass capacity is 1 metric ton or 1000 kg. Therefore the amount of people this can hold is simply the ratio of the maximum mass capacity over the mass of the person, that is:

people = 1000 kg / 91 kg

people = 10.98

 

So the elevator can safely occupy 10 people. We will not exceed to 11.

6 0
3 years ago
Read 2 more answers
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