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3 years ago

A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h

Physics

1 answer:

Nikolay [14]3 years ago

3 0

Answer:

Option A. 40 mi/h

Explanation:

To obtain the average speed of the vehicle, we'll begin by calculating the distance travelled by the vehicle in each case. This is illustrated below:

Case 1:

Speed = 30 mi/h

Time = 2 h

Distance =...?

Speed = Distance /Time

30 = Distance /2

Cross multiply

Distance = 30 × 2

Distance = 60 mi

Case 2:

Speed = 60 mi/h

Time = 1 h

Distance =...?

Speed = Distance /Time

60 = Distance /1

Cross multiply

Distance = 60 × 1

Distance = 60 mi

Finally, we shall determine the average speed of the vehicle as follow:

Total distance travelled = 60 + 60

Total distance travelled = 120 mi

Total time = 2 + 1

Total time = 3 h

Average speed =..?

Average speed = Total Distance travelled /Total time

Average speed = 120/3

Average speed = 40 mi/h

Therefore, the average speed of the vehicle is 40 mi/h

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2 years ago

A sail boat moves north for a distance of 10 km when blown by a wind 30° east of south with the force of 5.00×10^4 N. how much w

erma4kov [3.2K]

<h3><u>Answer;</u></h3>

a) 5.00 x 10^8 J

<h3><u>Explanation;</u></h3>

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2 years ago

If distance between two charges increased 5 times then force between them

Marrrta [24]

decreased 5 times

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3 years ago

A professor sits at rest on a stool that can rotate without friction. The rotational inertia of the professor-stool system is 4.

Anestetic [448]

Answer:

$\omega=0.37 [rad/s]$

Explanation:

We can use the conservation of the angular momentum.

$L=mvR$

$I\omega=mvR$

Now the Inertia is I(professor_stool) plus mR², that is the momentum inertia of a hoop about central axis.

So we will have:

$(I_{proffesor - stool}+mR^{2})\omega=mvR$

Now, we just need to solve it for ω.

$\omega=\frac{mvR}{I_{proffesor-stool}+mR^{2}}$

$\omega=\frac{1.5*2.7*0.4}{4.1+1.5*0.4^{2}}$

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I hope it helps you!

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3 years ago

According to the photon energy formula, tripling the frequency of the radiation from a monochromatic source will change the ener

Harrizon [31]

Answer:

By a factor of 3

Explanation:

In the photon energy formula , frequency and the energy content have a direct relationship. This means anything that is done to one of the parameters is the same that will be done to the other to have a balance.

In this equation: Energy=plank’s constant * frequency.

Energy is directly proportional to frequency.

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3 years ago

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