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3 years ago

What happens when the fuel in a car engine combustion?

1 answer:

5 0

In a spark ignition engine, the fuel is mixed with air and then inducted into the cylinder during the intake process. After the piston compresses the fuel-air mixture, the spark ignites it, causing combustion. The expansion of the combustion gases pushes the piston during the power stroke.

Credit: Department of Energy

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Two physics students, Ben and Bonnie, are in the weightlifting room. Bonnie lifts the 50 kg barbell over her head (approximately

KatRina [158]

Answer:

Both of them

Explanation:

5 0

3 years ago

The more mass an object has,the less inertia the object has. True or False

dedylja [7]

Answer:

This is true. objects that have a greater mass has greater interia. which also means objects that have a less mass has also less interia.

Explanation:

i hope this helps!!!

7 0

3 years ago

Suppose a hydrogen atom in its ground state moves 130 cm through and perpendicular to a vertical magnetic field that has a magne

blagie [28]

Answer:a)1.11×10^-21Nm

b) 1.16×10^-3m

Explanation:see attachment

5 0

4 years ago

A tennis ball hits with an initial velocity of 25 m/s [10 o above the

Sav [38]

First, calculate the components of its initial velocity v0:

v0x = v0cos10 = 24.6 m/s

v0y = v0sin10 = 4.34 m/s

The ball reaches its peak when vy = 0. Let's calculate the time it takes for vy to become zero:

vy = v0y - gt ---> t = v0y/g = 0.44 s

The horizontal distance it travels in this time is

x = v0xt = (24.6 m/s)(0.44 s)

= 10.8 m

Note that the net is 15 m away. After traveling a horizontal distance of 10.8 m, the height of the ball is

y = -(1/2)gt^2 + v0yt + 2.1

= -(4.9 m/s^2)(0.44 s)^2 + (4.34 m/s)(0.44 s) + 2.1 m

= -0.95 m + 1.9 m + 2.1 m

= 3.05 m

Note that this is the height of the ball at its peak. While the ball is well above the net at its peak, it is well short of its required horizontal distance to clear it. Instead, let's find the time it takes for the tennis ball to travel a horizontal distance of 15 m first:

x = v0xt ----> t = x/v0x = (15 m)/(24.6 m/s) = 0.61 s

Then calculate the height y when t = 0.61 s. If y > 0.9 m (height of the net), then the ball will clear the net.

y = -4.9t^2 + v0yt + 2.1

= -4.9(0.61 s)^2 + (4.34 m/s)(0.61 s) + 2.1 m

= -1.82 m + 2.65 m + 2.1 m

= 2.93 m

Yes, the ball will clear the net by 2.03 m.

3 0

3 years ago

An lc circuit oscillates at a frequency of 2000 Hz. What will the frequency be if the inductance is quadrupled?

Irina-Kira [14]

<h2>Answer:</h2>

An LC circuits if formed by an inductor and a capacitor. The charge on the capacitor and the current through the inductor both vary sinusoidally with time. Also, energy is transferred between magnetic energy in the inductor and electrical energy in the capacitor. But <em>what happens with the frequency if the inductance is quadrupled? </em>that is, if initially the inductance is $L$ and the frecuency $f=2000Hz$ if now $L_{New}=4L$ What will the frequency be? Well, we know that the frequency, inductance and capacitance are related as:

$f=\frac{1}{2\pi}\sqrt{\frac{1}{LC}}$

and this equals 2000Hz. If now L is quadrupled:

$f_{1}=\frac{1}{2\pi}\sqrt{\frac{1}{4LC}}=\frac{1}{2\pi}\sqrt{\frac{1}{4}}\sqrt{\frac{1}{LC}} \\ \\ \therefore f_{1}=(\frac{1}{2})\frac{1}{2\pi}\sqrt{\frac{1}{LC}} \\ \\ \\ Since \ f=\frac{1}{2\pi}\sqrt{\frac{1}{LC}} \ then: \\ \\ f_{1}=\frac{1}{2}f \therefore f_{1}=\frac{2000}{2} \\ \\ \therefore \boxed{f_{1}=1000Hz}$

<em>Finally, if L is quadrupled the frequency is half the original frequency and equals 1000Hz</em>

3 0

3 years ago

What happens when the fuel in a car engine combustion?​

What happens when the fuel in a car engine combustion?