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Bas_tet [7]
3 years ago
7

What happens when the fuel in a car engine combustion?​

Physics
1 answer:
Trava [24]3 years ago
5 0

In a spark ignition engine, the fuel is mixed with air and then inducted into the cylinder during the intake process. After the piston compresses the fuel-air mixture, the spark ignites it, causing combustion. The expansion of the combustion gases pushes the piston during the power stroke.

Credit: Department of Energy

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Solid state physics uses the. Theory to understand how the large-scale properties of solids result from their atomic scale struc
kondaur [170]

Answer:

Quantum theory

Explanation:

The scientific foundation in quantum mechanics is quantum theory, which describes the existence and behavior of mass and antimatter at the subatomic particles levels. Quantum theory and quantum theory are often related to as the existence and behavior of matter in the universe at that stage.

8 0
3 years ago
Which part of the electromagnetic spectrum has a lower frequency than visible light?
Mademuasel [1]

The Correct Answer is <u>D.Infrared/</u> <em>INFARED has a lower frequency than visible light/</em>

6 0
3 years ago
Read 2 more answers
1. Which of the following identifies the part of blood shown in B and describes its function? (1 point)
Lelechka [254]
White blood cells fight boy invaders to the body.
6 0
3 years ago
A 57 kg skier starts from rest at a height of H = 27 m above the end of the ski-jump ramp. As the skier leaves the ramp, his vel
Hatshy [7]

Answer:

(a)h=5.95m

(b) h is the same

Explanation:

According to the law of conservation of energy:

E_i=E_f\\U_i+K_i=U_f+K_f

The skier starts from rest, so K_i=0 and we choose the zero point of potential energy in the end of the ramp, so U_f=0. We calculate the final speed, that is, the speed when the skier leaves the ramp:

mgH=\frac{mv^2}{2}\\v=\sqrt{2gH}\\v=\sqrt{2(9.8\frac{m}{s^2})(27m)}\\v=23\frac{m}{s}

Finally, we calculate the maximum height h above the end of the ramp:

v_f^2=v_i^2-2gh\\

The initial vertical speed is given by:

v_i=vsin\theta

and the final speed is zero, solving for h:

h=\frac{v_i^2}{2g}\\h=\frac{((23\frac{m}{s})sin(28^\circ))^2}{2(9.8\frac{m}{s^2})}\\h=5.95m

(b) We can observe that the height reached does not depend on the mass of the skier

3 0
4 years ago
(correct answers only)
Gennadij [26K]

The time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.

<h3>Time of motion of the star fish</h3>

The time taken for the star fish to travel the given distance is calculated as follows;

s = ut + ¹/₂at²

55 = 11.8t + (0.5)(6.39)t²

55 = 11.8t + 3.195t²

3.195t² + 11.8t - 55 = 0

<em>solve the quadratic equation using formula method,</em>

where;

a = 3.195, b = 11.8, c = -55

t = 2.7 s

Thus, the time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

6 0
3 years ago
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