Ask question

Ask question

All categories

2 years ago

7

What happens when the fuel in a car engine combustion?

1 answer:

Trava [24]2 years ago

5 0

In a spark ignition engine, the fuel is mixed with air and then inducted into the cylinder during the intake process. After the piston compresses the fuel-air mixture, the spark ignites it, causing combustion. The expansion of the combustion gases pushes the piston during the power stroke.

Credit: Department of Energy

You might be interested in

Explain why energy from the sun cannot reach us by conduction or convection?

34kurt

Answer:

It cannot reach us by conduction or convection as there is no medium such as air in most part of the space between the earth and the sun. From the sun the heat comes to us by another process known as radiation. The transfer of heat by radiation does not require any medium.

8 0

2 years ago

Read 2 more answers

Express the answer to 4.31x10^7 multiplied by 5.41x10^5 scientific notation.

I am Lyosha [343]

Answer:

The product of the two numbers is 2.33* 10^13

Explanation:

Given

4.31x10⁷ and 5.41x10⁵

Required

Multiply

The multiplication of the two digits is represented as thus:

$Result = 4.31 * 10^7 * 5.41 * 10^5$

This can also be rewritten as

$Result = 4.31 * 5.41 * 10^7 * 10^5$

Multiply 4.31 and 5.41

$Result = 23.3171 * 10^7 * 10^5$

Apply laws of indices

$Result = 23.3171 * 10^{7+5}$

$Result = 23.3171 * 10^{12}$

The scientific notation is always in the form: $a * 10^n$

Where $1 \leq\ a \leq 10$

So:

23.3171 can be rewritten as 2.33171 * 10

So, we have:

$Result = 2.33171 * 10* 10^{12}$

Also, apply law of indices again

$Result = 2.33171 * 10^{1+12}$

$Result = 2.33171 * 10^{13}$

It's always advisable (but not compulsory to approximate to 1 or 2 decimal places)

So:

$Result = 2.33* 10^{13}$

<em>Hence; the product of the two numbers is 2.33* 10^13</em>

7 0

3 years ago

A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4. 5 m/s. What is the car’s change in momentum d

kodGreya [7K]

Answer:

Explanation:

Change in car's momentum = 700 * [4.5 - {-29)] = 23,450 kgm/s

4 0

2 years ago

A certain fuel-efficient hybrid car gets gasoline mileage of 55.0 mpg (miles per gallon). (a) If you are driving this car in Eur

ololo11 [35]

We will start by defining the units and their respective equivalences between the proposed measurement systems

$1km = 0.6214mi$

$1gallon = 3.788 litres$

PART A ) The mileage of the car is 55mpg (Miles per gallon)

$55mpg = 55(\frac{miles}{gallon}) (\frac{1km}{0.6214miles})(\frac{1gallon}{3.788L})$

$55mpg = 23.4km/L$

Therefore the mileage of the car is 23.4km/L

PART B ) The mileage of the car means that the car travels 23.4km and consumes 1 liter of fuel. Then

$1L = 23.4km$

For the car to travel 1500km the amount of fuel would be,

$1500km= (1500km)(\frac{1L}{23.4km})$

$1500km = 64.1L$

But 1 gas tank can only hold 45Liters of fuel, then the number of tank required would be

$\text{Number of tanks required} = \frac{64.1L}{45L}$

$\text{Number of tanks required} = 1.4tanks$

Thus the number of tanks of gas required to drive 1500km is 1.4

6 0

3 years ago

PLEASE HELP ME I AM TIMED!

Crank

Answer:

violet has the highest frequency

Explanation:

7 0

3 years ago