Who is the father of nuclear physics?

Modern telescopes are capable of seeing bright galaxies up to about

marishachu [46]

Answer:

Modern telescopes are capable of seeing bright galaxies up to about 10000 millions light years away

Explanation:

A telescope is a tool that astronomers use to see faraway objects. Most telescopes work by using curved mirrors to gather and focus light from the night sky. The bigger the mirrors or lenses, the more light the telescope can gather.

Modern telescopes gather information from the electromagnetic spectrum far beyond the range of visible light.

The farthest bright galaxies, that the modern telescope is capable of seeing is 10000 millions light years away.

5 0

4 years ago

According to Einstein’s theory, how does an increase in the number of photons affect a beam of light?

ludmilkaskok [199]

The answer is the third choice, "the brightness of the beam of light increases"

According to Einstein’s theory, an increase in the number of photons (per unit are) affects a beam of light by causing a higher intensity. <span> Sometimes, the term "brightness" is used when referring to the </span>intensity<span> of a color, a</span><span>lthough there are instances where this can be a misleading term when we try to describe </span><span>intensity</span>

7 0

3 years ago

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A student makes measurements from which she calculates the speed of sound as 327.66m/s She estimates that her result is accurate

Dmitry [639]

In this item, there needs to be a basis as to how many significant numbers can be present in a certain figure. If the answer 327.66 m/s is to be expressed as a 3 significant figures only, the answer would have to be 328. What was done here is to simply round up the units digit of the number since the decimal place (tenths) digit has a value of greater than 4.

The answer to this item is therefore letter B.

7 0

3 years ago

Correctly label the following structures surrounding the small intestine. Stomach Appendix lleum Cecum Jejunum Ascending colon

kifflom [539]

The structures that are surrounding the small intestine in the image are: stomach, ascending colon, cecum and appendix.

<h3>What is the small intestine?</h3>

The small intestine will be part of the digestive system and it is the smallest part of the intestine, it will be after the stomach and before the ascending colon. It will be made up of three parts: duodenum, which is the one attached to the stomach, ileum, and jejunum.

Each of its parts is going to have certain specific functions related to digestion, absorption and have immunity as a function.

Among the characteristics of the small intestine, absorption stands out since its surface is created for better absorption, since it will have circular folds, intestinal villi and microvilli. These will increase the absorption surface, so it works better.

To learn more about small intestine visit: brainly.com/question/24180887

#SPJ1

7 0

2 years ago

A 0.30-kg object connected to a light spring with a force constant of 22.6 N/m oscillates on a frictionless horizontal surface.

gtnhenbr [62]

Answer:

(a) vmax = 0.34m/s

(b) v = 0.13m/s

(c) v = 0.31m/s

(d) x = 0.039m

Explanation:

Given information about the spring-mass system:

m: mass of the object = 0.30kg

k: spring constant = 22.6 N/m

A: amplitude of the motion = 4.0cm = 0.04m

(a) The maximum speed of the object is given by the following formula:

$v_{max}=\omega A$ (1)

w: angular frequency of the motion.

The angular frequency is calculated with the following relation:

$\omega=\sqrt{\frac{k}{m}}$ (2)

You replace the expression (2) into the equation (1) and replace the values of the parameters:

$v_{max}=\sqrt{\frac{k}{m}}A=\sqrt{\frac{22.6N/m}{0.30kg}}(0.04m)=0.34\frac{m}{s}$

The maximum speed of the object is 0.34 m/s

(b) If the object is compressed 1.5cm the amplitude of its motion is A = 0.015m, and the maximum speed is:

$v_{max}=\sqrt{\frac{22.6N/m}{0.30kg}}(0.015m)=0.13\frac{m}{s}$

The speed is 0.13m/s

(c) To find the speed of the object when it passes the point x=1.5cm, you first take into account the equation of motion:

$x=Acos(\omega t)$

You solve the previous equation for t:

$t=\frac{1}{\omega}cos^{-1}(\frac{x}{A})\\\\\omega=\sqrt{\frac{22.6N/m}{0.30kg}}=8.67\frac{rad}{s}\\\\t=\frac{1}{8.67}cos^{-1}(\frac{1.5cm}{4.0cm})=0.13s$

With this value of t, you can calculate the speed of the object with the following formula:

$v=\omega Asin(\omega t)\\\\v=(8.67rad/s)(0.04m)sin((8.67rad/s)(0.13s))=0.31\frac{m}{s}$

The speed of the object for x = 1.5cm is v = 0.31 m/s

(d) To calculate the values of x on which v is one-half the maximum speed, you first calculate the time t:

$\frac{v_{max}}{2}=\omega A sin(\omega t)\\\\t=\frac{1}{\omega}sin^{-1}(\frac{v_{max}}{2\omega A})\\\\t=\frac{1}{8.67rad/s}sin^{-1}(\frac{0.13m/s}{2(8.67rad/s)(0.04m)})=0.021s$

The position will be:

$x=Acos(\omega t)=0.04mcos((8.67rad/s)(0.021s))=0.039m$

The position of the object on which its speed is one-half its maximum velocity is 0.039

5 0

4 years ago

Who is the father of nuclear physics?​

Who is the father of nuclear physics?