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Art [367]
3 years ago
15

What is the net charge on a sphere that has the following? a) 5.29 x 10^6 electrons and 7.07 x 10^6 protons

Physics
1 answer:
e-lub [12.9K]3 years ago
3 0

Answer:

Explanation:

Electrons will create negative and protons will create positive charge . 5.29 x 10⁶ electrons will neutralize same no of protons . So

( 7.07 - 5.29 ) x 10⁶ protons will create net positive charge

magnitude of this charge can be calculated as follows

   no of protons x charge on one proton

(7.07 - 5.29)x 10⁶ x 1.6 x 10⁻¹⁹ C

2.848 X 10⁻¹³ C is the net charge on the sphere. Ans

b )

Protons and electrons have equal but opposite charges .

115 protons will neutralize the charge of 115 electrons .

225-115 = 110 electrons will remain un-neutralized .

Charge on these un-neutralized electrons will be calculated as follows .

no of electrons x charge on a single electrons

110 x 1.6 x 10⁻¹⁹ C

176 X 10⁻¹⁹C is the net charge on the sphere.   Ans

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An electron in a cathode-ray beam passes between 2.5cm long parallel-plate electrodes that are 6.0mm apart. A 2.1mT, 2.5-cm-wide
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Answer:

(a). The speed of electron is 1.56\times10^{7}\ m/s.

(b). The radius of electron is 4.2\ cm

Explanation:

Given that,

Length = 2.5 cm

Distance = 6.0 mm

Magnetic field = 2.1 T

Potential difference = 700 V

(a). We need to calculate the electron's speed

Using formula of speed

v=\sqrt{\dfrac{2eV}{m}}

Put the value into the formula

v=\sqrt{\dfrac{2\times1.6\times10^{-19}\times700}{9.1\times10^{-31}}}

v=15689290.81\ m/s

v=1.56\times10^{7}\ m/s

(b). We need to calculate the radius of electron

Using formula of centripetal force

\dfrac{mv^2}{r}=qvB

r=\dfrac{mv}{qB}

Where,

m = mass of electron

v = speed of electron

r = radius

q = charge of electron

B = magnetic field

Put the value into the formula

r=\dfrac{9.1\times10^{-31}\times1.56\times10^{7}}{1.6\times10^{-19}\times2.1\times10^{-3}}

r=0.042\ m

r=4.2\ cm

Hence, (a). The speed of electron is 1.56\times10^{7}\ m/s.

(b). The radius of electron is 4.2 cm

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3 years ago
HELP ASAP PLEASE PHYSICS
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Answer: did you get the answers?

Explanation:

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