Answer:
0 m/s²
Explanation:
Since each skater pushes the other with a force of 70 N, according to Newton's third law, there is an equal reaction and thus the other pushes back with a force of 70 N in the other direction, so we have forces of +70N and -70 N respectively. So, the net force on each skateboarder is F = + 70 N + (-70 N) = + 70 N - 70 N = 0 N.
Since force, F = ma where a = acceleration and m = mass,
a = F/m.
So, since for each skater, F = 0N,
a = 0 N/m
= 0 m/s²
So, the acceleration of each skater is 0 m/s²
