Answer:
Explanation:
Let c be the circumference and r be the radius
c = 2πr , r = c / 2π , area A = π r² = π (c/2π )² = (1/4π) x c²
flux (ψ) = BA = 1 X 1/4π X c²
dψ/dt = 1/4π x 2c dc/dt =1/2π x c x dc/dt
at t = 8 s
c = 161 - 13 x 8 = 57 cm , dc/dt = 13 cm/s
e = dψ/dt = (1 / 2π )x 57 x 13 x 10⁻⁴ = 118 x 10⁻⁴ V.
Answer:
The answer is C
Explanation:
The magnitude of the gravitational force depends inversely on the square of the radial distance between the centers of the two masses. Thus, essentially, the force can only fall to zero, when the denominator that is r becomes infinite.
Explanation:
The magnitude of a vector v can be found using Pythagorean's theorem.
||v|| = √(vₓ² + vᵧ²)
||v|| = √((-309)² + (187)²)
||v|| ≈ 361
You can find the angle of a vector using trigonometry.
tan θ = vᵧ / vₓ
tan θ = 187 / -309
θ ≈ 149° or θ ≈ 329°
vₓ is negative and vᵧ is positive, so θ must be in the second quadrant. Therefore, θ ≈ 149°.
Answer:

Explanation:
We have an uniformly accelerated motion, with a negative acceleration. Thus, we use the kinematic equations to calculate the distance will it take to bring the car to a stop:

The acceleration can be calculated using Newton's second law:

Recall that the maximum force of friction is defined as
. So, replacing this:

Now, we calculate the distance:

Opposite to the direction of the velocity which led it to its current position.
Explanation:
The direction of momentum when a vertically oscillating block comes to the rest momentarily will be opposite to the direction of the velocity that it has just followed to reach reach its current position.
The direction of change in momentum at the bottom will be upwards and at the top will be downwards.
The change in momentum is mathematically defined as:

where:
mass of the block
final velocity of the block
initial velocity of the block
When the block comes to rest it is due to the result of continuously decreasing velocity.