The masses of the two moons are determined to be 2M2M for Moon AA and MM for Moon BB . It is observed that the distance between
2 answers:
Answer:
F_A = 8 F_B
Explanation:
The force exerted by the planet on each moon is given by the law of universal gravitation
F =
where M is the mass of the planet, m the mass of the moon and r the distance between its centers
let's apply this equation to our case
Moon A
the distance between the planet and the moon A is r and the mass of the moon is 2m
F_A = G \frac{2m M}{r^{2} }
Moon B
F_B = G \frac{m M}{(2r)^{2} }
F_B = G \frac{m M}{4 r^{2} }
the relationship between these forces is
F_B / F_A = = 1/8
F_A = 8 F_B
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Answer:
No the given statement is not necessarily true.
Explanation:
We know that the kinetic energy of a particle of mass 'm' moving with velocity 'v' is given by
Similarly the momentum is given by
For 2 particles with masses and moving with velocities
respectively the respective kinetic energies is given by
Similarly For 2 particles with masses and moving with velocities
respectively the respective momenta are given by
Now since it is given that the two kinetic energies are equal thus we have
Thus we infer that the moumenta are not equal since the ratio on right of 'i' is not 1 , and can be 1 only if the velocities of the 2 particles are equal which becomes a special case and not a general case.