Answer:
Supongo que queremos determinar la carga de la carga de prueba.
Sabemos que la fuerza culombiana entre dos cargas q₁ y q₂, separadas por una distancia R, está dada por:
Aislandolo para una de las cargas, obtenemos:
En este caso sabemos:
fuerza atractiva, por lo que los signos de las cargas son opuestos.
q₁ = 5 mC
R = 35cm
F = 1.5 N
Kc = 9*10^9 N*m^2/C^2
Un primer paso, seria reescribir todos los valores en las mismas unidades.
Sabiendo que:
100cm = 1m
R = 35cm = (35/100) m = 0.35m
Y sabiendo que:
1mc = 1*10^(-6) C
Entonces:
q₁ = 5 mC = 5*1*10^(-6) C = 5*10^(-6) C
Ahora podemos reemplazar esos valores en la ecuación de la fuerza, para obtener el valor de la otra carga:
Y recordar que las cargas tienen signo opuesto, entonces la carga de la carga de prueba es:
q₂ = -4.08*10^-5 C
Answer:
Earth orbits the Sun at an average distance of 149.60 million km (92.96 million mi), and one complete orbit takes 365.256 days (1 sidereal year), during which time Earth has traveled 940 million km (584 million mi).
Explanation:
Answer:
electrons are transferred from the wool shirt to the plastic rod is 4.375 × 
electrons
Explanation:
given data
Amount of charge transferred Q = -0.7 μC = -0.7 × 
C
electrons of charge e = -1.6 × 
C
solution
we apply formula here for total charge of electrons that is
Q = n × e ...................2
here n is no of electron that is
n = 
put here value
n = 
n = 4.375 × electrons
so here electrons are transferred from the wool shirt to the plastic rod is 4.375 × electrons
Answer:
The rate of change of position in which the same distance is traveled each second is called uniform velocity.
Explanation:
- When there is a change in the position coordinate of an object with respect to time, it is has a velocity associated with it.
- Similarly, when there is a change in the velocity component of the object with respect to the time, there is an acceleration associated with it.
- When the rate of change of position in which the same distance is traveled each second, the object is said to be in uniform velocity. Therefore, there is no acceleration acting on the object.
- Since there is no acceleration acting on the object, the net force on the object is zero.
