Imma guess A! Idk if it’s 100% correct tho so I’d check that!
To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.
The work done would be defined as
Where,
PE = Potential Energy
KE = Kinetic Energy
Where,
m = Mass
g = Gravitational energy
h = Height
v = Velocity
Considering power as the change of energy as a function of time we will then have to
The rate of mass flow is,
Where,
= Density of water
A = Area of the hose
The given radius is 0.83cm or m, so the Area would be
We have then that,
Final the power of the pump would be,
Therefore the power of the pump is 57.11W
You can make sure there's no change in volume by keeping
your gas in a sealed jar with no leaks. Then you can play with
the temperature and the pressure all you want, and you'll know
that the volume is constant.
For 'ideal' gases,
(pressure) times (volume) is proportional to (temperature).
And if volume is constant, then
(pressure) is proportional to (temperature) .
So if you increase the temperature from 110K to 235K,
the pressure increases to (235/110) of where it started.
(400 kPa) x (235/110) = 854.55 kPa. (rounded)
Obviously, choice-b is the right one, but
I don't know where the .46 came from.
<u>Answer:</u>
The acceleration of the car is
<u>Explanation:</u>
In the question it is given that car initially heads north with a velocity . It then accelerates for and in the end its velocity is .
initial velocity
time
final velocity
The equation of acceleration is
The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.