Answer:
a. Heat Capacity = 1.756J/mol-K
b. Heat Capacity = 24.942J/mol-k
Explanation:
Given
Constant volume Cv = 0.81J/mol-k
T1 = 34K
Td = Debye temperature = 306 K. Estimate the heat capacity (in J/mol-K) a. 44 K
First, The value of the temperature-independent constant.
Using Cv = AT³
Make A the subject of formula
A = Cv/T³
Substitute each values
A = 0.81/34³
A = 0.000020608589456543
A = 2.061 * 10^-5J/mol-k
The heat capacity changes with the temperature; below is the relationship between heat capacity and the temperature
Cv = AT³
So, The heat capacity when T = 44k is then calculated as
Cv = 2.061 * 10^-5 * 44³
Cv = 1.755522084266232
Cv = 1.756J/mol-K
(b) at 477 K.
Because the temperature is larger than the Debye temperature, the specific heat is calculated using as:
Cv = 3R
Where R = universal gas constant
R = 8.314J/mol-k
Cv = 3 * 8.314
Cv = 24.942J/mol-k
Answer:
The requirement does not meet the feasibility standard.
Explanation:
because the people can just put on the blackbelts
Answer:
The phase current in each line conductor are;
Explanation:
Given the following data;
Red phase = 24kW,
Yellow phase = 18kW
Blue phase = 12kW
Line voltage = 415V
For a star connected system, we have;
The phase sequence for RYB is given by;
<em>For the Red phase;</em>
<em>For the Yellow phase;</em>
<em>For the Blue phase;</em>
For the line neutral;
Substituting we have,
Answer:
ExplanationAir at 1 atm and 20°C flows tangentially on both sides of a thin, smooth flat plate of ... ... Smooth Flat Plate Of Width W = 10 Ft, And Of Length L 3 Ft In The Direction Of The Flow. The Velocity Outside The Boundary Layer Is Constant At 20 Ft/s.
: