An engineering drawing shows the: (A) dimensions, tolerances, cost, and sales or use volume of a component.(B) dimensions, toler
1 answer:
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Answer:
for t = 1 : ( x1 , y1 ) = (1,2)
for t = 2 : ( x2, y2 ) = (2,4)
for t = 3 : ( x3, y3 ) = ( 0,-3)
for t = 4 : ( x4, y4 ) = ( 0,-4)
Explanation:
Attached below is the detailed solution and the sketch
we have to make assumptions for the various values of t and integrate accordingly
for t = 1 : ( x1 , y1 ) = (1,2)
for t = 2 : ( x2, y2 ) = (2,4)
for t = 3 : ( x3, y3 ) = ( 0,-3)
for t = 4 : ( x4, y4 ) = ( 0,-4)
Given data :
origin ( x = 0, y = 0 )
u = 1 m/s, v = 2 m/s,
where u = 0 m/s v = -1 m/s
Answer:
Compute the number of gold atoms per cubic centimeter = 9.052 x 10^21 atoms/cm3
Explanation:
The step by step and appropriate substitution is as shown in the attachment.
From number of moles = Concentration x volume
number of moles = number of particles/ Avogadro's number
Volume = mass/density, the appropriate derivation to get the number of moles of atoms
