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Vanyuwa [196]
3 years ago
10

An engineering drawing shows the: (A) dimensions, tolerances, cost, and sales or use volume of a component.(B) dimensions, toler

ances, materials, and finishes of a component.(C) materials, finishes, machining operations, and dimensions of a component.(D) cost, materials, tolerances, and lead-time for a component.(E) cost, dimensions, and machining operations for a component.
Engineering
1 answer:
Leto [7]3 years ago
3 0

Answer:

(B) dimensions, tolerances, materials, and finishes of a component.

Explanation:

An engineering drawing :

  An  engineering drawing is a technical drawing which draws the actual component .

An engineering drawing shows

1. Materials

2.Dimensions

3.Tolerance

4.Finishes of a component

Engineering drawing does not shows any information about the cost of component.

So the option B is correct.

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9 Consider fully developed conditions in a circular tube with constant surface temperature Ts Tm. Determine whether a small- or
mojhsa [17]

Answer:

Hello your question is incomplete attached below is the complete question

answer:

Considering Laminar flow

Q ( heat )  will be independent of diameter

Considering Turbulent flow

The heat transfer will increase with decreasing "dia" for the turbulent

heat transfer = f(d^-0.8 )

Explanation:

attached below is the detailed solution

Considering Laminar flow

Q ( heat )  will be independent of diameter

Considering Turbulent flow

The heat transfer will increase with decreasing "dia" for the turbulent

heat transfer = f(d^-0.8 )

6 0
3 years ago
forty gal/min of a hydrocarbon fuel having a spesific gravity of 0.91 flow into a tank truck with load limit of 40,000 lb of fue
Zina [86]

Answer: 131.75minutes

Explanation:

First if all, we've to find the density of liquid which will be:

= Specific gravity × Density to pure water

= 0.91 × 8.34lb/gallon

= 7.59lb/gallon

Then, the volume that's required to fill the tank will be:

= Load limit/Density of fluid

= 40000/7.59

= 5270.1gallon

Now, the time taken will be:

= V/F

= 5270.1/40

= 131.75min

It'll take 131.75 minutes to fill the tank in the truck.

5 0
3 years ago
Name two types of fabric testers and explain how they work.
Lilit [14]

Answer:

Merchandisers are the key persons in apparel business. They work as a bridge between buyer and seller. Merchandisers have to do various tasks from order execution to final dispatch. Developing Lab dip is one of the primary jobs for a merchandiser to start an order execution. They need to run for lab dip approval. Though this would be an easy task, sometimes big mistakes may occur. They have to do different fabric tests as buyer required. In this article I will briefly described different types of fabric test are completed by garment merchandisers.

It is necessary to validate the information that the mill or manufacturer gives you. This is normally done by having fabric tested by an accredited testing house (internationally recognized) either in the country of manufacturer or locally in your head office. Some companies have their own equipment and employ qualified fabric technicians to carry out the testing at their headquarters. When using an accredited testing house, it will not matter in which country the test is done, because the test has to be carried out to the agreed method, and no matter which country does the test, it will be done in exactly the same way. As the fabric construction is such an important part of the garment, when finalized, the fiber composition, weight, and yarn count should be added to your contract with the supplier.

The testing house will give you guidance on the result you should be achieving and the method that you should be using.

4 0
4 years ago
A car weighs 600 lbf on a planet where the gravitational acceleration is 6 ft/s^2. What is the car’s weight on Earth?
Mice21 [21]

Answer:

14308 N

Explanation:

See it in the pic.

6 0
4 years ago
A forklift raises a 90.5 kg crate 1.80 m. (a) Showing all your work and using unity conversion ratios, calculate the work done b
klasskru [66]

Answer:

(a) Work done is 1.59642 kJ

(b) Useful power supplied = 0.1298 kW

Explanation:

(a) Work done = mass of crate × acceleration due to gravity × distance = 90.5 kg × 9.8 m/s^2 × 1.8 m = 1596.42 kgm^2/s^2 × 1 J/1 kgm^2/s^2 × 1 kJ/1000 J = 1.59642 kJ

(b) Useful power supplied = work done ÷ time = 1.59642 kJ ÷ 12.3 s = 0.1298 kJ/s × 1 kW/1 kJ/s = 0.1298 kW

5 0
3 years ago
Read 2 more answers
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