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astraxan [27]
3 years ago
5

Five hundred joules of heat are added to a closed system. The initial internal energy of the system is 87 J, and the final inter

nal energy is 134 J. How much work is being done by the system?
A) 221 J
B) 279 J
C) 366 J
D) 453 J
Physics
2 answers:
mina [271]3 years ago
8 0
The answer is D. i got all the other ones wrong ._.

timurjin [86]3 years ago
6 0
<h3><u>Answer;</u></h3>

453 Joules

<h3><u>Explanation;</u></h3>
  • The change in internal energy = Final energy -initial energy

       = 134 J - 87 J

          = 47 Joules

  • Energy added to the closed system is 500 joules
  • Work done = energy added to the system -Change in internal energy

                  = 500 Joules - 47 Joules

                   = 453 joules

The work done is therefore,<em><u> 453 joules.</u></em>


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What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the
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The acceleration of the wagon along the ground is 3.6 m/s².

To solve the problem above, we need to use the formula of acceleration as related to force and mass.

Acceleration: This can be defined as the rate of change of velocity.

⇒ Formula:

  • Fcos∅ = ma................. Equation 1

⇒ Where:

  • F = Force
  • ∅ = angle above the horizontal
  • m = mass of the wagon
  • a = acceleration of the wagon

⇒ make a the subject of equation 1

  • a = Fcos∅/m..................... Equation 2

From the question,

⇒ Given:

  • F = 44 N
  • ∅ = 35°
  • m = 10 kg

⇒ Substitute these values into equation 2

  • a = 44(cos35°)/10
  • a = 44(0.8191)/10
  • a = 3.6 m/s²

Hence, The acceleration of the wagon along the ground is 3.6 m/s²

Learn more about acceleration here: brainly.com/question/9408577

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A solar-powered car is traveling at constant speed around a circular track. what happens to the centripetal acceleration of the
anyanavicka [17]
Centripetal acceleration is the acceleration of an object acted upon a force that pulls it toward the center of origin. For constant speed, there is no acceleration, since acceleration is defined as the difference of velocities at an elapsed time. Hence, if speed doubles, then the centripetal acceleration would increase as well.
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A pendulum is swinging next to a wall. The distance from the bob of the pendulum to the wall varies in a periodic way that can b
nexus9112 [7]

The formula of the trigonometric function that models the distance HHH from the pendulum's bob to the wall after t seconds is

H(t) = 15 -6sin(2.5π(t -0.5))

Detailed explanation:

The function can be expressed as the following for the midline M, amplitude A, period T, and time t0 at which the function deviates from the midline:

 H(t) = M -Asin(2π/T(t -t0))

The equation is based on the parameters M=15, A=6, T=0.8, and t0 = 0.5.

H(t) is equal to 15 -6sin(2.5π(t -0.5))

<h3>What is function?</h3>

The trigonometric functions in mathematics are real functions that connect the right-angled triangle's angle to the ratios of its two side lengths .In all areas of study that involve geometry, such as geodesy, solid mechanics, celestial mechanics, and many others, they are widely used.

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The correct question is:

A pendulum is swinging next to a wall. The distance from the bob of the swinging pendulum to the wall varies in a periodic way that can be modeled by a trigonometric function.

The function has period 0.80.80, point, 8 seconds, amplitude 6 \text{ cm}6 cm6, start text, space, c, m, end text, and midline H = 15 \text{ cm}H=15 cmH, equals, 15, start text, space, c, m, end text. At time t = 0.5t=0.5t, equals, 0, point, 5 seconds, the bob is at its midline, moving towards the wall.

Find the formula of the trigonometric function that models the distance HHH from the pendulum's bob to the wall after t seconds. Define the function using radians.

5 0
2 years ago
Lactic acid is produced during low-moderate exercise <br> True <br> False
Marizza181 [45]
The answer to your question is true.
3 0
3 years ago
Read 2 more answers
A 1.5 kg spherical ball is has a radius of 50 cm is rotating with angular velocity of 12 revolutions per minute. Determine the r
kykrilka [37]

Answer:

K.E = 0.0075 J

Explanation:

Given data:

Mass of the ball = 1.5 kg

radius, r = 50 cm = 0.5 m

Angular speed, ω = 12 rev/min = (12/60) rev/sec = 0.2 rev/sec

Now,

the kinetic energy is given as:

K.E = K.E=\frac{1}{2}I\omega^2

where,

I is the moment of inertia = mr²

on substituting the values, we get

K.E=\frac{1}{2}\times1.5\times0.5^2\times0.2^2

or

K.E = 0.0075 J

3 0
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