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3 years ago

14

Help Please! a lot of points for 3 questions

1 answer:

s344n2d4d5 [400]3 years ago

4 0

Answer:

1. Point 2.

2. Either #1 or #4 (sorry, I'm not 100% sure).

3. I'm pretty sure #3.

I hope this helps!

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A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east

elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: $56.31^o$

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

$d=\sqrt{9^2+6^2} \\d=\sqrt{81+36} \\d=\sqrt{117} \\d=10.82 \,\,km$

Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle $\theta$ , we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

$tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\$

Now we can find the value of the angle by using the arctan function:

$tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o$

6 0

3 years ago

I HAVE A PHYSICS TEST, ITS 25 QUESTIONS AND I HAVE ABOUT AN HOUR TO SOLVE IT. PLEASE IF YOU’RE GOOD AT PHYSICS CONTACT ME ASAP

Katena32 [7]

Answer:

in which Class u studying

5 0

3 years ago

Read 2 more answers

A roller coaster moving down a hill is an example of what kind of energy

GalinKa [24]

That would be kinetic energy

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3 years ago

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A 48.5 kg student runs down the sidewalk and jumps with a horizontal speed of 4.25 m/s onto a stationary skateboard. The student

storchak [24]

<u>Answer:</u>

2.39 kg

<u>Explanation:</u>

There is conservation of momentum here in this problem so we will use the following problem:

$m_1u_1+m_2u_2=(m_1+m_2)v$

where the mass of the student $m_1$ is 48.5 kg,

the mass of the skateboard $m_2$ is $m_2$ kg,

the initial speed of the student $u_1$ is 4.25 m/s; and

the speed of the student and skateboard $v$ is 4.05 m/s.

So substituting the given values in the above formula to get:

$(48.5*4.25) + (m_2 * 0) = (48.5 + m_2 ) * 4.05$

$206.125=196.425+4.05m_2$

$206.125 - 196.425 = 4.05m_2$

$m_2=\frac{9.7}{4.05}$

$m_2=2.39$

Therefore, the mass of the skateboard is 2.39 kg.

7 0

3 years ago

You are traveling in a car that is moving at a velocity of 30 m/s. Suddenly, a car 15 meters in front of you slams on its brakes

Artemon [7]

Answer:

The acceleration of car is 6.67 m/s².

Explanation:

Given that,

Initial velocity = 30 m/s

Distance = 15 m

Final velocity = 10 m/s

Time = 3 sec

We need to calculate the acceleration

Using formula of acceleration

$a=\dfrac{v_{f}-v_{i}}{t}$

$a=\dfrac{10-30}{3}$

$a=\dfrac{-20}{3}$

$a=-6.67\ m/s^2$

Negative sign shows the car is slowing down.

Hence, The acceleration of car is 6.67 m/s².

7 0

4 years ago