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mina [271]
4 years ago
5

Kepler's second law: as a planet moves around its orbit, it sweeps out ______areas in ______ times.

Physics
1 answer:
natali 33 [55]4 years ago
6 0
<span>Kepler's second law: as a planet moves around its orbit, it sweeps out  EQUAL areas in EQUAL times.

</span>
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A player kicks a ball across the grass. what causes the ball to slow down to stop
vlada-n [284]

Answer: Friction

Explanation: Friction caused m by the ball rubbing against the grass and ground cause it to lose energy in the form of thermal energy and slow down

7 0
4 years ago
A tennis ball with a velocity of +10.0 m/s to the right is thrown perpendicularly at a wall. After striking the wall, the ball r
netineya [11]

Answer:

-1500 m/s2

Explanation:

So the ball velocity changes from 10m/s into the wall to -8m/s in a totally opposite direction within a time span of 0.012s. Then we can calculate the average acceleration of the ball as the change in velocity over a unit of time.

a = \frac{\Delta v}{\Delta t} = \frac{-8 - 10}{0.012} = \frac{-18}{0.012} = -1500 m/s^2

6 0
3 years ago
What is the relationship between the spring constant and the period in a mass hanging on a spring oscillation and why?
anygoal [31]

Explanation:

Period of a mass on a spring is:

T = 2π√(m/k)

T is inversely proportional with the square root of k.  So as the spring constant increases, the period decreases.

3 0
3 years ago
Read 2 more answers
1. How much force is needed to accelerate a 66 kg skier<br> at 2 m/sec2?
Tju [1.3M]

Answer:

<h2>132 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 66 × 2

We have the final answer as

<h3>132 N</h3>

Hope this helps you

3 0
3 years ago
An object increases its velocity from 22 m/s to 36 m/s in 5.0 s. What is the average velocity of the object?
Luden [163]

Answer:

a=2.8\ m/s^2

Explanation:

Given that,

Initial velocity of an object, u = 22 m/s

Final velocity of an object, v = 36 m/s

Time, t = 5 s

It can be assumed to find the average acceleration of the object instead of average velocity.

The change in velocity per unit time is equal to average acceleration of an object. It can be given by :

a=\dfrac{v-u}{t}\\\\a=\dfrac{36\ m/s-22\ m/s}{5}\\\\\a=\dfrac{14}{5}\ m/s^2\\\\a=2.8\ m/s^2

So, the acceleration of the object is 2.8\ m/s^2.

7 0
3 years ago
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