Question

A university student earned grades 84, 78, 84, and 72 on his four regular tests. He earned a grade of 78 on the final exam and 86 on his class projects. His combined homework grade was 87. The four regular tests count for 40% of the final grade, the final exam counts for 30%, the project counts for 10%, and the homework counts for 20%. What is his weighted mean grade? Round to one decimal place.

Answer 1

Answer:

His weighted mean grade is 81.2.

Step-by-step explanation:

His weighed mean grade is given by the following formula:

$M = 0.40RT + 0.30F + 0.10P + 0.20H$

We have that RT is the mean of the regular tests. The student earned grades 84, 78, 84, and 72 on his four regular tests. So the mean is

$RT = \frac{84+78+84+72}{4} = 79.5$

F is the grade on the final exam. He earned a grade of 78 on the final exam, so $F = 78$

P is the grade of the project. So $P = 86$.

H is the homework grade, so $H = 87$.

So

$M = 0.40RT + 0.30F + 0.10P + 0.20H$

$M = 0.40(79.5) + 0.30(78) + 0.10(86) + 0.20(87) = 81.2$

His weighted mean grade is 81.2.