Answer:
beed points sorry really sorry
Answer:
![\textsf{A)}\quad y=-\sqrt{x}+2](https://tex.z-dn.net/?f=%5Ctextsf%7BA%29%7D%5Cquad%20y%3D-%5Csqrt%7Bx%7D%2B2)
Step-by-step explanation:
Parent function:
![y = \sqrt{x}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%7Bx%7D)
The properties of the parent function are:
- Starts at the origin, so y-intercept is at (0, 0)
- Domain: x ≥ 0
- Range: y ≥ 0
- As x increases, y increases
From inspection of the graph, as the x-values increase, the y-values decrease. Therefore there has been a <u>reflection in the x-axis</u>.
The y-intercept is now at (0, 2), therefore the function has been <u>translated 2 units up</u>.
<u>Translations</u>
For a > 0
![y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}](https://tex.z-dn.net/?f=y%3D-f%28x%29%20%5Cimplies%20f%28x%29%20%5C%3A%20%5Ctextsf%7Breflected%20in%20the%7D%20%5C%3A%20x%20%5Ctextsf%7B-axis%7D)
![f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}](https://tex.z-dn.net/?f=f%28x%29%2Ba%20%5Cimplies%20f%28x%29%20%5C%3A%20%5Ctextsf%7Btranslated%7D%5C%3Aa%5C%3A%5Ctextsf%7Bunits%20up%7D)
Therefore:
Reflected in the x-axis: ![-f(x)=-\sqrt{x}](https://tex.z-dn.net/?f=-f%28x%29%3D-%5Csqrt%7Bx%7D)
Then translated 2 units up: ![-f(x)+2=-\sqrt{x}+2](https://tex.z-dn.net/?f=-f%28x%29%2B2%3D-%5Csqrt%7Bx%7D%2B2)
So the equation that represents the transformed function is:
![y=-\sqrt{x}+2](https://tex.z-dn.net/?f=y%3D-%5Csqrt%7Bx%7D%2B2)
Heptagon has seven sides.
Enzo and Beatriz are playing games at their local arcade.
Incredibly, Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of total tickets.
What is the minimum number of games that Enzo could have played?
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Hint: the minimum # of tickets to be equal is 5*11 = 55
The area of the portion of the windshield cleaned by the 10-in wiper blade is 106.85in² .
We have been provided that the Length of blade is 15 inches and the Angle of rotation = 98°
We are required to calculate the area of the portion of the windshield cleaned by the 10-in wiper blade.
We have to solve this by using area of a sector.
Area of a sector = ½r²θ
where θ is in radians.
So, angle of rotation (98°) must first be converted to radians
Converting 98º to radians, we get
98×π/180 = 49π/90
The area of the region swept out by the wiper blade
= (area of the sector where r = 15 and θ = 49π/90) - (area of the sector where r = (15-10) and θ = 49π/90).
So, Area = ½×15²×49π/0 - ½×5²×49π/90
= ½×49π/90(15²-10²)
= 49π/180× (225 - 100)
= 49π/180 × 125
= 1225π/36
Area = 106.8472in²
=106.85 in²
Hence, the area of the portion of the windshield cleaned by the 10-in wiper blade is 106.85in²
To know more about area of a sector- brainly.com/question/7512468
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