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rosijanka [135]
3 years ago
5

A spring with a spring constant of 50 N/m is stretched by an extension of 2 cm. Calculate the energy in its elastic energy poten

tial store. Use the equation: elastic potential energy = 1/2 × spring constant × extension²
Physics
1 answer:
MAVERICK [17]3 years ago
6 0

Answer:

0.01 J

Explanation:

E = ½ kx²

E = ½ (50 N/m) (0.02 m)²

E = 0.01 J

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Answer:

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so<em> v=at</em>

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putting values:

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