A spring with a spring constant of 50 N/m is stretched by an extension of 2 cm. Calculate the energy in its elastic energy poten
tial store. Use the equation: elastic potential energy = 1/2 × spring constant × extension²
1 answer:
Answer:
0.01 J
Explanation:
E = ½ kx²
E = ½ (50 N/m) (0.02 m)²
E = 0.01 J
You might be interested in
It is false. The effect of freezing is almost the exact opposite
Answer:
Subtract the atomic number from the mass number
Explanation:
The number of neurons in an atom is equal to the difference between the atomic number and the mass number
The Soviet Union's Sputnik 1, it was launched October 4th 1957.
