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Nonamiya [84]
4 years ago
13

What happens when a mechanical wave travels through a medium? Question 1 options: a) Waves are transferred. b) Mass is transferr

ed. c) Particles are transferred. d) Energy is transferred.
Physics
1 answer:
ladessa [460]4 years ago
3 0
D. Energy is transferred
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Two 100 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Bat -10 m/s when th
tatiyna

Answer:

b) -10 m/s

Explanation:

In perfectly elastic head on collisions of identical masses, the velocities are exchanged with one another.

3 0
3 years ago
At an accident scene on a level road, investigators measure a car's skid mark to be 88 m long. It was a rainy day and the coeffi
german

Answer:

The speed was 26.91m/s (96.9 km/h)

Explanation:

Here you have to consider that at the beginning you have an amount of kinetic energy (K) that is dissipated because of the work done by friction forces (T). Since the car is stopped after the accident, all the energy has been dissipated. Thus, K=T.

The definition of the kinetic energy is K=1/2*m*v^2.

The work done by the friction forces is: T=f*(m*g)*d. Where <em>f</em> is the friction coefficient, <em>g</em> is the gravity acceleration, <em>m i</em>s the mass of the car and <em>d</em> is the skid marks longitude. Therefore,

1.2*m*v^2=f*(m*g)*d

Since <em>m</em> is in both sides it can be cancelled so it is not necessary to considered.

Then, the speed is determined by the following equation:

v=\sqrt{2*f*g*d} =\sqrt{2*0.42*9.8m/s^2*88 m}=26.91 m/s

4 0
3 years ago
If two point sources that create circular waves are moved closer together, what happens to the spacing between the nodal and ant
Dennis_Churaev [7]

<span>The distance between the sources of a two point surface interference determines the number of lines that can be created for the nodal and anti-nodal lines. When the sources are moved closer together, the number of lines becomes minimal. Thus, the spaces between the lines become bigger. The answer to this item is letter A. The spacing increases. </span>

8 0
3 years ago
A bucket filled with water has a mass of 54 kg and is hanging from a rope that is wound around a 0.050 m radius stationary cylin
Lubov Fominskaja [6]

Answer:

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

Explanation:

Given that,

Mass of bucket = 54 kg

Radius = 0.050 m

We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder

Using formula of torque

\tau=F\times r

\tau=mg\times r

Where, m = mass

g = acceleration due to gravity

r = radius

Put the value into the formula

\tau=54\times9.8\times0.050

\tau=26.46\ N-m

Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

3 0
3 years ago
A car moving at 10.0 m/s encounters a depression in the road that has a circular cross-section with a radius of 30.0 m. What is
Dennis_Churaev [7]

Answer:

F = 789 Newton

Explanation:

Given that,

Speed of the car, v = 10 m/s

Radius of circular path, r = 30 m

Mass of the passenger, m = 60 kg

To find :

The normal force exerted by the seat of the car when the it is at the bottom of the depression.

Solution,

Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.

N=mg+\dfrac{mv^2}{r}

N=m(g+\dfrac{v^2}{r})

N=60\times (9.81+\dfrac{(10)^2}{30})

N = 788.6 Newton

N = 789 Newton

So, the normal force exerted by the seat of the car is 789 Newton.

6 0
3 years ago
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