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netineya [11]
3 years ago
10

An object has a net force. The net force points in the south west direciton. Knowing this, what can you can you conclude about t

he accleration, and velocity of the object
Physics
1 answer:
madam [21]3 years ago
6 0

Answer:

1) The acceleration is in the SW direction.

2) It is not possible to make a conclusion regarding the direction of the velocity.

Explanation:

1)

  • According Newton's 2nd Law, the acceleration is directly proportional to the net force applied, and has the same direction than it.
  • Since the net force points in the SW direction, so does  the acceleration.

2)

  • By definition, acceleration is the rate of change of the velocity with respect to time.
  • Since acceleration is a vector, it can represent a change in  the magnitude of the velocity (if it speeds up or if it is slows down), along the same direction (NW or SW in this case), and/or a change in the direction, as in the circular movement case, in which acceleration and speed are perpendicular each other.
  • So, with the information that we have, we can't say in which direction the velocity points.
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Answer:

The semi truck travels at an initial speed of 69.545 meters per second downwards.

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m_{S}\cdot v_{S}+m_{C}\cdot v_{C} = (m_{S}+m_{C})\cdot v (1)

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m_{S}, m_{C} - Masses of the semi truck and the car, measured in kilograms.

v_{S}, v_{C} - Initial velocities of the semi truck and the car, measured in meters per second.

v - Final speed of the system after collision, measured in meters per second.

If we know that m_{S} = 2200\,kg, m_{C} = 2000\,kg, v_{C} = 45\,\frac{m}{s} and v = -15\,\frac{m}{s}, then the initial velocity of the semi truck is:

m_{S}\cdot v_{S} = (m_{S}+m_{C})\cdot v -m_{C}\cdot v_{C}

v_{S} = \frac{(m_{S}+m_{C})\cdot v - m_{C}\cdot v_{C}}{m_{S}}

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v_{S} = v +\frac{m_{C}}{m_{S}}\cdot (v-v_{C})

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