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tensa zangetsu [6.8K]
2 years ago
8

2. The weight of a boat without load is 12 000 N and the volume of the immersed portion of the boat is 5.0 m³. [ Density of sea

water is 1020 kg m-³] as shown in DIAGRAM 2 DIAGRAM 2 Calculate o The buoyant force exerted to the boat. The maximum mass of load that can be supported by the boat so that it will not sink completely.​

Physics
1 answer:
HACTEHA [7]2 years ago
6 0
The answer is 12 because …………………
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A Scooter with a mass of 50 kilograms travels with a speed of 10 meters per second. A 2 Nt force bring it to a halt. How long ti
Serga [27]

Answer:

250s

Explanation:

Given parameters:

Mass  = 50kg

Speed  = 10m/s

Force  = 2N

Unknown:

Time the force was acting  = ?

Solution:

To solve this problem, we use the equation of motion from the second law of Newton:

            Ft  = mV

F is the force

t is the time taken

m is the mass

V is the velocity

          2  x t  = 50 x 10

               t  = 250s

3 0
3 years ago
The quark composition of the proton and neutron are, respectively, uud and udd, where u is an up quark (charge +23e) and d is a
ludmilkaskok [199]

Answer:

Option C=> π+.

Explanation:

Just as it is given in the question above, we can see that the addition or combination of proton and neutron gives what is known as QUARKS.

Quarks are not easily measured because one can not see and study a quark independently; quarks move in multiples together.

The study of Quarks is very important in physics because they relate very well with electromagnetic force, strong force, weak force and Gravitational force.

"...When the remaining quarks combine to form a single particle, it is a π+".

π+ is a meson or a pion and it contains quarks and anti-quarks too

8 0
3 years ago
You push an object with 67 N of force and move it 20 m. How much work did you do?
Stella [2.4K]

Answer:

<h2>1340 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 67 × 20

We have the final answer as

<h3>1340 J</h3>

Hope this helps you

6 0
3 years ago
A plank rests on top of the axles of two identical wheels. Each wheel's outer radius is 0.25 meters and each wheel's axle has ra
kaheart [24]

Answer:

<u><em>The plank moves 0.2m from it's original position</em></u>

Explanation:

we can do this question from the constraints that ,

  • the wheel and the axle have the same angular speed or velocity
  • the speed of the plank is equal to the speed of the axle at the topmost point .

thus ,

<em>since the wheel is pure rolling or not slipping,</em>

<em>⇒v=wr</em>

where

<em>v - speed of the wheel</em>

<em>w - angular speed of the wheel</em>

<em>r - radius of the wheel</em>

<em>since the wheel traverses 1 m let's say in time 't' ,</em>

<em>v_{w}=\frac{distance}{time} =\frac{1}{t}</em>

∴

⇒w=\frac{v_{w}}{r} = \frac{1}{t*0.25}

the speed at the topmost point of the axle is :

⇒v_{a}=w*r\\v_{a}=\frac{1}{t*0.25} *0.05\\v_{a}=\frac{1}{5t}

this is the speed of the plank too.

thus the distance covered by plank in time 't' is ,

⇒d=v_{a}*t\\d=\frac{1}{5t} *t\\d=\frac{1}{5} = 0.2m

8 0
3 years ago
If an object is dropped from a tall building and hits the ground 3.0 s later, how tall is the building?
allsm [11]
D = 1/2 g t^2. It works out to 44.1 meters.
6 0
3 years ago
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