5.91(approx) seconds just divide velocity by acceleration
Answer:-q
Explanation:
Given
Capacitor is charged to a battery and capacitor acquired a charge of q i.e.
+q on Positive Plate and -q on negative Plate.
If the plate area is doubled and the plate separation is reduced to half its initial separation then capacitor becomes four times of initial value because capacitor is given by

where A=area of capacitor plate
d=Separation between plates
This change in capacitance changes the Potential such that new charge on the negative plate will remain same -q
Well momentum is = to Mass*Velocity so let's use an example to figure this out
If I weighed 50kg and I was jogging at 3m/s then I broke into a run at 6m/s how will me momentum be affected?
3m/s*50kg=150
6m/s*50kg=300
So as you can see by doubling the velocity you also double the momentum
Answer:

Explanation:
Given

Required
Determine the percentage error
First, we calculate the mean

This gives:



Next, calculate the mean absolute error (E)

This gives:
![|E| = \sqrt{\frac{1}{6}*[(1.54 - 1.51)^2 +(1.53- 1.51)^2 +.... +(1.45- 1.51)^2]}](https://tex.z-dn.net/?f=%7CE%7C%20%3D%20%5Csqrt%7B%5Cfrac%7B1%7D%7B6%7D%2A%5B%281.54%20-%201.51%29%5E2%20%2B%281.53-%201.51%29%5E2%20%2B....%20%2B%281.45-%201.51%29%5E2%5D%7D)



Next, calculate the relative error (R)



Lastly, the percentage error is calculated as:


Answer: the answer is D.Heat from the engine under the hood transfered to the snow, melting it.
Explanation: Heat always transfers from warmer objects to cooler objects. For example, if snow is on the hood of your car, as the engine warms up, heat will be transfered from the engine to the snow, melting the snow and cooling the engine.